Kindly provide the solution to the following question using the GRASS method. The images attached are the formulas for this unit (Dynamics) and the question. Please make sure to show all your work using the GRASS method, using formulas from the unit (Dynamics). MotionAd = Ad₁ + Ad₂ + ...bsin Basin AV₂ VtVAB = VAC + VCBa av==ForcesācF = ma=Csin Cc²=a² + b² sindtāav ( t)²2F = mã,Uniform Circular Motion1²F = may=-d = v₁ t+VXY =√xxā =v=x =FmF₂Unit 1 Dynamics=àtHcos-b+√b²-4ac2aF = mgGMmā=à = (v₁ + √₂) t2HV7.ttan 0 =1.AA==bhv² = ₁² +2αavF₁ = FNv=2-rV=Tc²=a² + b² - 2ab cos 0Y₂ Y₁X₂ X₁āav( t)²2āFA = lws,maxNSlope=d=v₂ ta = 4 ² rf² Tr=}V=FNGMr A car is moving along a banked highway on a ramp that is banked at an angle of 14.0°to the horizontal. The radius of curvature of the bank is 264 m and the coefficient offriction between the tires and the road is 0.67. What is the maximum speed that thecar can travel and safely stay on the ramp?

Answered: Image /qna-images/answer/041df904-12c4-4563-8270-140faff28e79.jpg

Answered: A car is moving along a banked highway…

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