A car has an initial speed of 30 m/s and starts to decelerate at a rate of 2.5 m/s2. How long will it take for the car to stop? 4.8 s O 24 s O 75 s O 12 s
A car has an initial speed of 30 m/s and starts to decelerate at a rate of 2.5 m/s2. How long will it take for the car to stop? 4.8 s O 24 s O 75 s O 12 s
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![### Physics Problem: Deceleration of a Car
#### Question:
A car has an initial speed of 30 m/s and starts to decelerate at a rate of 2.5 m/s². How long will it take for the car to stop?
#### Options:
- 4.8 s
- 24 s
- 75 s
- 12 s
This question is designed to test your understanding of the concepts of speed, deceleration, and time.
### Explanation:
To solve this problem, you can use the equation of motion for deceleration:
\[ v_f = v_i + at \]
Where:
- \( v_f \) is the final velocity (0 m/s, since the car comes to a stop)
- \( v_i \) is the initial velocity (30 m/s)
- \( a \) is the acceleration (here it will be negative because it's deceleration, -2.5 m/s²)
- \( t \) is the time in seconds
We need to solve for \( t \):
\[ 0 = 30 + (-2.5)t \]
Rearranging and solving for \( t \):
\[ 2.5t = 30 \]
\[ t = \frac{30}{2.5} \]
\[ t = 12 \, \text{seconds} \]
Thus, the car will take 12 seconds to come to a complete stop. The correct option is:
- 12 s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F607d9201-03cc-42fe-8512-621b5025ad41%2F5b05a9e2-8051-4ad7-a0bf-074c398cf682%2Ff03oc9o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Physics Problem: Deceleration of a Car
#### Question:
A car has an initial speed of 30 m/s and starts to decelerate at a rate of 2.5 m/s². How long will it take for the car to stop?
#### Options:
- 4.8 s
- 24 s
- 75 s
- 12 s
This question is designed to test your understanding of the concepts of speed, deceleration, and time.
### Explanation:
To solve this problem, you can use the equation of motion for deceleration:
\[ v_f = v_i + at \]
Where:
- \( v_f \) is the final velocity (0 m/s, since the car comes to a stop)
- \( v_i \) is the initial velocity (30 m/s)
- \( a \) is the acceleration (here it will be negative because it's deceleration, -2.5 m/s²)
- \( t \) is the time in seconds
We need to solve for \( t \):
\[ 0 = 30 + (-2.5)t \]
Rearranging and solving for \( t \):
\[ 2.5t = 30 \]
\[ t = \frac{30}{2.5} \]
\[ t = 12 \, \text{seconds} \]
Thus, the car will take 12 seconds to come to a complete stop. The correct option is:
- 12 s
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