A car accelerates from rest to a maximum speed of 20 m/s over a 20 s time interval. The net force on the car as afunction of time is given by Fnet = 3350 (t + 1)-1/2 where Fnet is measured in N and t goes from 0 to 20 s.Multiple Choice Questions:7) What is the impulse on the car as it accelerates from rest to its top speed?a) 1.8 × 104 N sb) 2.4 × 104 N. sc)3.8 × 104 N sd) 4.1 x 104 N. Se)5.8 × 104 N. sf)8.5 × 104 N. s8) Assume that the wheels on the car each have a diameter of 49 cm and that the outside edge of the wheelspins with a tangential velocity of 20 m/s. If each of the wheels has a moment of inertia I = 0.75 kg. m²,how much rotational kinetic energy does a single wheel have while traveling at this speed?a) O Jc)b) 120 Jd)478 J1913 JShort Answer Question (6 points)e) 2499 Jf) 7653 J

7. Option b is correct 2.4 * 10^4 N.s. 8. Option e is correct 2499 JExplanation:Step 1: Step 2:…

Answered: A car accelerates from rest to a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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ent G An impulse of 12.2 kg*m/s is deli x 361242/take 10 p Question 1 A warehouse employee is pushing a 30.0 kg desk across a floor at a constant speed of 0.50 m/s. What is the magnitude of the momentum of the desk? O 0.017 kg*m/s O 15.0 kg*m/s O 60 kg*m/s O 30.5 kg*m/s Question 2 10 pts Norton Antivirus: 19.99/YE Your special price is valid to Google Chrome istudy-helper.co The momentum of a 12kg dog racing to greet its owner has a Norton What is the dog's speed? Install O a Cop
The bumper of a car has a force sensor mounted inside which records the force vs time graph during crash testing. A particular collision occurs between t = 0.075s and t = 2.32s and can be modelled by the following function: F(t) = 4t4 – 80t² + 140t – 10 A graph of the collision is also provided below: Impulse 60 50 40 30 20 10 1 time (s) Part A The impulse during the collision will be while the maximum force experience by the bumper will be 75 kg · m/s, 33N 54 kg · m/s, 54N O 75 kg · m/s, 54N 54 kg · m/s, 33N (N) aɔ10
When there is motion is both directions, state which direction is positive at the START of the problem. For the impulse-momentum and the conservation of momentum problems: Plug your GIVEN VALUES into the equation FIRST then do the algebra. Use the following equations: F t = m vf -m vi m1 vi1 + m2 vi2 = m1 vf1 + m2 vf2 m1 vi1 + m2 vi2 = (m1 + m2) vf (m1 + m2) Vi = m1 vf1 + m2 vf2 6.) Ball 1 : m1 = 8 slugs and vi1 = 3 ft/s to the RIGHT Ball 2: m2 = 4 slugs and vi2 = 0 Ball 3: m3 = 6 slugs and vi3 = 0 picture the three balls all siting on a flat surface with some space between them. AFTER ball 1 strikes ball 2, ball 1 is traveling at 1.5 ft/s to the LEFT AFTER ball 2 strikes ball 3, ball 2 is traveling at 3 ft/s to the LEFT a,) What is the direction (left or right) and final velocity of ball 3? Vf3 =? Show all unit conversions step by step, if any.
E6.) A ball experiences a change in momentum of 24 kg-m/s.a. What is the impulse acting on the ball?b. If the time of interaction is 0.15 s, what is the magnitude of the average force acting on the ball? Answer with the correct formula.
When there is motion is both directions, state which direction is positive at the START of the problem. For the impulse-momentum and the conservation of momentum problems: Plug your GIVEN VALUES into the equation FIRST then do the algebra. Use the following equations: F t = m vf -m vi m1 vi1 + m2 vi2 = m1 vf1 + m2 vf2 m1 vi1 + m2 vi2 = (m1 + m2) vf (m1 + m2) Vi = m1 vf1 + m2 vf2 2. ) The baseball is traveling at 90 mph to the left towards the batter. The batter strikes the 0.05 slug baseball with a force of 50.00 lbs. The bat is in contact with the softball for 0.25 seconds. Assume that the baseball is traveling directly in the opposite direction after being hit with the bat. a. what is the velocity of the baseball after being hit by the batter? show all unit conversions-if any, step by step.
Suppose F₁ = 2000 N. (Figure 1) You may want to review (Pages 262-266). Figure F, (N) F 0- 0 N. 2 4 6 1 of 1 -t (ms) Part A What impulse does the force shown in the figure exert on a 250 g particle? Express your answer in newton-seconds to two significant figures. WD ΑΣΦ J = Submit Previous Answers Request Answer X Incorrect; Try Again Provide Feedback ? N.S
An astronaut floating at rest in space throws a wrench in one direction and subsequently recoils back with a velocity in the opposite direction. Which of the following statements is/are true? 1. The velocity of the wrench is equal and opposite to the velocity of the astronaut. II. The momentum of the wrench is equal and opposite to the momentum of the astronaut. III. The impulse applied to the wrench is equal and opposite to the impulse applied to the astronaut. II and III only I only Il only I, II, and III I and II only
If the impulse acting on a moving 100 kg object is zero, what does that mean about the velocity of the object? Recall that impulse is: F*t = m*Δv where Δv = vf - vi vf > vi vf = vi vf < vi Not enough information to determine.
A mass m1= 3kg slides down slippery ramp, reaching a speed v=9 m/s at the bottom. After reaching the level ground m1 collides with mass m2= 4kg at bottom, sticking together in a perfectly inelastic collision. The combined mass then slides over a floor, finally coming to rest after travelling a horizontal distance x= 6m. a.) What was the height of the ramp, assuming that m1 started from rest? b.) How fast were the combined masses m1 and m2 moving after sticking together?
A blue pool ball (p = 33 kg x m/s) moves towards a red pool ball (p = -13 kg x m/s). Then, the two pool balls collide. After the collision, the blue pool ball has no momentum. How much momentum does the red pool ball have after the collision? Explain your answer.
Impulse and momentum problem: A stationary 1.25-kg object is struck by a stick. The object experiences a horizontal force given by F = 1,520{N/(ms)} t - 19{N/(ms)2}t2, where t is the time in milliseconds from the instant the stick first contacts the object. What is the speed of the object just after it comes away from the stick at t = 2.11 ms? (Give answer to the nearest 0.1 m/s)
A time-varying horizontal force of F(t) = ßt3 acts on an object for 1.46 seconds, starting from t = 0 s. A Calculate the magnitude of the impulse on the object from the applied force if B = 9.19 N/s³. J = O Search @ kg m/s 7:58 PM 11/29/2022

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