College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
100%
![### Understanding Impulse and Momentum
Impulse and momentum are fundamental concepts in physics that describe the motion of objects. Here's a breakdown of the key principles and equations involved:
#### Key Equations:
1. **Momentum (p)**
\[
p = mv
\]
* \( p \) = momentum
* \( m \) = mass (in kilograms)
* \( v \) = velocity (in meters per second)
2. **Impulse (J)**
\[
J = Ft
\]
* \( J \) = impulse
* \( F \) = force applied (in Newtons)
* \( t \) = time over which the force is applied (in seconds)
3. **Impulse-Momentum Theorem**
\[
Ft = m \Delta v
\]
* \( F \) = force
* \( t \) = time
* \( m \) = mass
* \( \Delta v \) = change in velocity
#### Problem Statement
What impulse is needed to stop a 1700 kg car in 15 seconds if it was originally moving at 25 m/s?
To solve this problem, we need to find the impulse (\( J \)) required to bring the car to a stop. We are given:
- Mass of the car (\( m \)) = 1700 kg
- Initial velocity (\( v \)) = 25 m/s
- Final velocity (\( v_f \)) = 0 m/s (since the car stops)
- Time (\( t \)) = 15 seconds
Using the Impulse-Momentum Theorem (\( Ft = m \Delta v \)), we can calculate the impulse.
First, determine the change in velocity (\( \Delta v \)):
\[
\Delta v = v_f - v = 0 - 25 = -25 \, \text{m/s}
\]
Then, calculate the impulse:
\[
J = m \Delta v
\]
\[
J = 1700 \times (-25)
\]
\[
J = -42500 \, \text{Ns}
\]
The negative sign indicates that the impulse is in the direction opposite to the car's initial motion in order to bring it to a stop. Thus, the magnitude of the impulse needed is **42500 Ns**.
This example illustrates how to apply the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb95dca4-f6c7-46fa-bbcb-5cdbe2ca0e09%2F09a18b58-52aa-4bf1-9fa3-d223506e416f%2Fcoha3pd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Impulse and Momentum
Impulse and momentum are fundamental concepts in physics that describe the motion of objects. Here's a breakdown of the key principles and equations involved:
#### Key Equations:
1. **Momentum (p)**
\[
p = mv
\]
* \( p \) = momentum
* \( m \) = mass (in kilograms)
* \( v \) = velocity (in meters per second)
2. **Impulse (J)**
\[
J = Ft
\]
* \( J \) = impulse
* \( F \) = force applied (in Newtons)
* \( t \) = time over which the force is applied (in seconds)
3. **Impulse-Momentum Theorem**
\[
Ft = m \Delta v
\]
* \( F \) = force
* \( t \) = time
* \( m \) = mass
* \( \Delta v \) = change in velocity
#### Problem Statement
What impulse is needed to stop a 1700 kg car in 15 seconds if it was originally moving at 25 m/s?
To solve this problem, we need to find the impulse (\( J \)) required to bring the car to a stop. We are given:
- Mass of the car (\( m \)) = 1700 kg
- Initial velocity (\( v \)) = 25 m/s
- Final velocity (\( v_f \)) = 0 m/s (since the car stops)
- Time (\( t \)) = 15 seconds
Using the Impulse-Momentum Theorem (\( Ft = m \Delta v \)), we can calculate the impulse.
First, determine the change in velocity (\( \Delta v \)):
\[
\Delta v = v_f - v = 0 - 25 = -25 \, \text{m/s}
\]
Then, calculate the impulse:
\[
J = m \Delta v
\]
\[
J = 1700 \times (-25)
\]
\[
J = -42500 \, \text{Ns}
\]
The negative sign indicates that the impulse is in the direction opposite to the car's initial motion in order to bring it to a stop. Thus, the magnitude of the impulse needed is **42500 Ns**.
This example illustrates how to apply the
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you

College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning

University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press

College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning

University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press

Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning

Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley

College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON