- A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces have magnitudes F₁ = 7 kip, F₂ = 6 kip, and F3 = 9 kip. The truss is held in equilibrium by a pin at point A and a roller at point G. The lengths for members DE, EF, and FG is s = 6 ft and for member AG is h = 15 ft. Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated from low-carbon steel with a yield strength of Sy = ±32 ksi. Using the method of sections, determine the minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of SF = 2.1 with respect to yielding. - Note: Express tension forces as positive (+) and compression forces as negative (-). F₁ h A G S B L F S F₂ C E S F3 D

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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AAB =
ABF=
AEF=
0
0
0.236
in²
in²
in²
?
X 0%
x 0%
X 0%
Transcribed Image Text:AAB = ABF= AEF= 0 0 0.236 in² in² in² ? X 0% x 0% X 0%
A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces
have magnitudes F₁ = 7 kip, F₂ = 6 kip, and F3 = 9 kip. The truss is held in equilibrium by a pin at point A
and a roller at point G. The lengths for members DE, EF, and FG is s = 6 ft and for member AG is h = 15 ft.
Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated
from low-carbon steel with a yield strength of Sy = ±32 ksi. Using the method of sections, determine the
minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of
SF = 2.1 with respect to yielding.
Note: Express tension forces as positive (+) and compression forces as negative (-).
F₁
h
AAB
ABF=
0
0
A
G
S
B
3
S
in²
(?) X0%
F₂
C
E
S
F₁
3
D
Transcribed Image Text:A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces have magnitudes F₁ = 7 kip, F₂ = 6 kip, and F3 = 9 kip. The truss is held in equilibrium by a pin at point A and a roller at point G. The lengths for members DE, EF, and FG is s = 6 ft and for member AG is h = 15 ft. Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated from low-carbon steel with a yield strength of Sy = ±32 ksi. Using the method of sections, determine the minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of SF = 2.1 with respect to yielding. Note: Express tension forces as positive (+) and compression forces as negative (-). F₁ h AAB ABF= 0 0 A G S B 3 S in² (?) X0% F₂ C E S F₁ 3 D
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