A cannon, located 60.0 m from the base of a vertical15.0-m-tall cliff, shoots a 15 kg shell at 43.0° above thehorizontal toward the cliff.What must the minimum muzzle velocity be for the shell to clear the top of the cliff?Express your answer with the appropriate units.V0, min = 28.4SubmitCorrectPart BmSPrevious AnswersThe ground at the top of the cliff is level, with a constant elevation of 15.0 m above the cannon. Under the conditions of the previous part, how fardoes the shell land past the edge of the cliff?Express your answer with the appropriate units.AL = 82.02HÅmSubmit Previous Answers Request Answer?Review | ConstantsX Incorrect; Try Again; 3 attempts remaining

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A cannon, located 60.0 m from the base of a vertical 15.0-m-tall cliff, shoots a 15 kg shell at 43.0° above the horizontal toward the cliff.