A cannon ball is launched into the air with an upward velocity of 359 feet tall cannon. The height h of the cannon ball after t seconds can be found using the eq h = – 16t2 + 359t + 13. per second, Approximately how long later will the cannon be at 1329 feet high? Round answers to tenth if necessary. units: Hint: List all of the solutions with commas between them. Hint: Be sure to include the units. How long later will it hit the ground? * units:

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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A cannon ball is launched into the air with an upward velocity of 359 feet per second, from a 13-foot
tall cannon. The height h of the cannon ball after t seconds can be found using the equation
h = – 16t2 + 359t + 13.
Approximately how long later will the cannon be at 1329 feet high? Round answers to the nearest
tenth if necessary.
units:
Hint: List all of the solutions with commas between them.
Hint: Be sure to include the units.
How long later will it hit the ground?
o units:
Question Help: D Video
Transcribed Image Text:A cannon ball is launched into the air with an upward velocity of 359 feet per second, from a 13-foot tall cannon. The height h of the cannon ball after t seconds can be found using the equation h = – 16t2 + 359t + 13. Approximately how long later will the cannon be at 1329 feet high? Round answers to the nearest tenth if necessary. units: Hint: List all of the solutions with commas between them. Hint: Be sure to include the units. How long later will it hit the ground? o units: Question Help: D Video
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