A cannon ball is fired with an initial speed of 123 m/s at angle of 60 degrees from the horizontal. Express the initial velocity as a linear combination of its unit vector components. ( m/s) + ( m/s) At the maximum height, the speed of the cannon ball is v = m/s and the magnitude of its acceleration is a = m/s2. The time needed to reach maximum height is t = s. The maximum height reached by the cannon ball is H = m.

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Q: A cannon ball is fired with an initial speed of 123 m/s at angle of 60 degrees from the horizontal.…

A: Hello. Since your question has multiple sub-parts, we will solve the first three sub-parts for you.…

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Q: magnitude and direction (angle) of the position vector one second after launch

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Q: velocity

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Projectile Motion