The acceleration of a particle moving only on a horizontal xy plane is given by a = 3t i +4rj, where a is in meters per second-squared and t is in seconds. At t = 0, the position vector is 7 = (20 m) i +(40 m) j and the velocity vector V = (5 m/s) i +(2 m/s) j. Find expressions for the (a) x and (b) y component (in meters) of the position of the particle at time t. (c) What is the angle between its velocity and the positive direction of the x axis at time t? (а) х - +5t+20]i m Edit (b) у в Edit (с) в - Edit

The acceleration of a particle moving only on a horizontal xy plane is given by a = 3t i +4rj, where a is in meters per second-squared and t is in seconds. At t = 0, the position vector is 7 = (20 m) i +(40 m) j and the velocity vector V = (5 m/s) i +(2 m/s) j. Find expressions for the (a) x and (b) y component (in meters) of the position of the particle at time t. (c) What is the angle between its velocity and the positive direction of the x axis at time t? (а) х - +5t+20]i m Edit (b) у в Edit (с) в - Edit

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section1.8: Some Properties Of Vectors

Problem 1.4QQ

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The acceleration of a particle moving only on a horizontal xy plane is given by á = 3t i+4t j, where á is in meters per second-squared and t is in seconds. At t = 0, the position vector is 7 = (20 m) i+(40 m) j and the velocity vector
v = (5 m/s) i+(2 m/s) j. Find expressions for the (a) x and (b) y component (in meters) of the position of the particle at time t. (c) What is the angle between its velocity and the positive direction of the x axis at time t?
(а) х %3D
5t+20) i m
Edit
(b) y =
Edit
(c) e =
Edit
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