The acceleration of a particle moving only on a horizontal xy plane is given by a = 3t i +4rj, where a is in meters per second-squared and t is in seconds. At t = 0, the position vector is 7 = (20 m) i +(40 m) j and the velocity vector V = (5 m/s) i +(2 m/s) j. Find expressions for the (a) x and (b) y component (in meters) of the position of the particle at time t. (c) What is the angle between its velocity and the positive direction of the x axis at time t? (а) х - +5t+20]i m Edit (b) у в Edit (с) в - Edit

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The acceleration of a particle moving only on a horizontal xy plane is given by á = 3t i+4t j, where á is in meters per second-squared and t is in seconds. At t = 0, the position vector is 7 = (20 m) i+(40 m) j and the velocity vector
v = (5 m/s) i+(2 m/s) j. Find expressions for the (a) x and (b) y component (in meters) of the position of the particle at time t. (c) What is the angle between its velocity and the positive direction of the x axis at time t?
(а) х %3D
5t+20) i m
Edit
(b) y =
Edit
(c) e =
Edit
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Transcribed Image Text:The acceleration of a particle moving only on a horizontal xy plane is given by á = 3t i+4t j, where á is in meters per second-squared and t is in seconds. At t = 0, the position vector is 7 = (20 m) i+(40 m) j and the velocity vector v = (5 m/s) i+(2 m/s) j. Find expressions for the (a) x and (b) y component (in meters) of the position of the particle at time t. (c) What is the angle between its velocity and the positive direction of the x axis at time t? (а) х %3D 5t+20) i m Edit (b) y = Edit (c) e = Edit Click if you would like to Show Work for this question: Open Show Work
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