A camera is accidentally dropped from a helicopter at a height of 4,096 ft. If the equation for height as a function of time is h(t) = -16t2 + initial height where t is time in seconds and h(t) is height in feet, how many seconds will it take for the camera to hit the ground? %3D [?] seconds

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Problem Statement

**Scenario:** 
A camera is accidentally dropped from a helicopter at a height of 4,096 ft. 

**Given Data:**
The equation for height as a function of time \( h(t) \) is:
\[ h(t) = -16t^2 + \text{initial height} \]

where
- \( t \) is time in seconds.
- \( h(t) \) is height in feet.

**Objective:**
Determine the number of seconds it will take for the camera to hit the ground.

**Equation:**
Plugging in the initial height:

\[ h(t) = -16t^2 + 4096 \]

**Solution:**
To find the time \( t \) when the camera hits the ground, set \( h(t) \) to 0 and solve for \( t \):
\[ 0 = -16t^2 + 4096 \]

Rearranging the equation gives:
\[ 16t^2 = 4096 \]

Dividing both sides by 16:
\[ t^2 = 256 \]

Taking the square root of both sides:
\[ t = \sqrt{256} \]
\[ t = 16 \]

Hence, it will take **16 seconds** for the camera to hit the ground.

#### Input Field:
- **[?] seconds** - Enter the calculated time in seconds into this field.

#### Answer:
16 seconds
Transcribed Image Text:### Problem Statement **Scenario:** A camera is accidentally dropped from a helicopter at a height of 4,096 ft. **Given Data:** The equation for height as a function of time \( h(t) \) is: \[ h(t) = -16t^2 + \text{initial height} \] where - \( t \) is time in seconds. - \( h(t) \) is height in feet. **Objective:** Determine the number of seconds it will take for the camera to hit the ground. **Equation:** Plugging in the initial height: \[ h(t) = -16t^2 + 4096 \] **Solution:** To find the time \( t \) when the camera hits the ground, set \( h(t) \) to 0 and solve for \( t \): \[ 0 = -16t^2 + 4096 \] Rearranging the equation gives: \[ 16t^2 = 4096 \] Dividing both sides by 16: \[ t^2 = 256 \] Taking the square root of both sides: \[ t = \sqrt{256} \] \[ t = 16 \] Hence, it will take **16 seconds** for the camera to hit the ground. #### Input Field: - **[?] seconds** - Enter the calculated time in seconds into this field. #### Answer: 16 seconds
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