Part A and B A bullet of mass 90 grams, traveling at 120 m/sec, strikes a stationary aluminum block ( M = 3.00 kg)and penetrates through the block with the velocity of 40 m/sec,(Before)(After) MmVIA→ Vo174713. find the velocity of the block after the collision.a. 3.60 m/sb. 3.50 m/sc. 4.80 m/sVZZZ Vd. 2.40 m/s14. find the percent energy loss during collision: by taking the difference and divided by initial kinetic energy.a. 72 %b. 86 %c. 88%d. 75%

Before collision A mass of bullet (m) = 0.09 kg velocity of bullet (ui) = 120 m/s Mass of block (M)…

Answered: A bullet of mass 90 grams, traveling at…

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