A bullet of mass 90 grams, traveling at 120 m/sec, strikes a stationary aluminum block ( M = 3.00 kg) and penetrates through the block with the velocity of 40 m/sec, (Before) → V TU!!! M 13. find the velocity of the block after the collision. a. 3.60 m/s b. 3.50 m/s M (After) c. 4.80 m/s * ZZZ √ d. 2.40 m/s 14. find the percent energy loss during collision : by taking the difference and divided by initial kinetic energy. a. 72 % b. 86 % c. 88 % d. 75%
A bullet of mass 90 grams, traveling at 120 m/sec, strikes a stationary aluminum block ( M = 3.00 kg) and penetrates through the block with the velocity of 40 m/sec, (Before) → V TU!!! M 13. find the velocity of the block after the collision. a. 3.60 m/s b. 3.50 m/s M (After) c. 4.80 m/s * ZZZ √ d. 2.40 m/s 14. find the percent energy loss during collision : by taking the difference and divided by initial kinetic energy. a. 72 % b. 86 % c. 88 % d. 75%
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Part A and B
Transcribed Image Text:A bullet of mass 90 grams, traveling at 120 m/sec, strikes a stationary aluminum block ( M = 3.00 kg)
and penetrates through the block with the velocity of 40 m/sec,
(Before)
(After) M
m
VIA
→ Vo
1747
13. find the velocity of the block after the collision.
a. 3.60 m/s
b. 3.50 m/s
c. 4.80 m/s
V
ZZZ V
d. 2.40 m/s
14. find the percent energy loss during collision: by taking the difference and divided by initial kinetic energy.
a. 72 %
b. 86 %
c. 88%
d. 75%
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