A bullet of mass 0.016 kg traveling horizontally at a high speed of 300 m/s embeds itself in a block of mass 3 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds Itself in the block? m/s (b) Calculate the total translational kinetic energy before and after the collision. Kerans Krans (c) Compare the two results and explain why there is a difference. O The Energy Principle isn't valid for an inelastic collision. The internal energy of the block-bullet system has increased. O Some of the momentum is lost in an inelastic collision.

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A bullet of mass 0.016 kg traveling horizontally at a high speed of 300 m/s embeds itselr in a block of mass 3 kg that is sitting at rest on a nearly frictionless
surface.
(a) What is the speed of the block after the bullet embeds Itself in the block?
m/s
(b) Calculate the total translational kinetic energy before and after the collision.
Krans
Krans,"
(c) Compare the two results and explain why there is a difference.
O The Energy Principle isn't valid for an inelastic collision.
The internal energy of the block-bullet system has increased.
O Some of the momentum is lost in an inelastic collision.
Transcribed Image Text:A bullet of mass 0.016 kg traveling horizontally at a high speed of 300 m/s embeds itselr in a block of mass 3 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds Itself in the block? m/s (b) Calculate the total translational kinetic energy before and after the collision. Krans Krans," (c) Compare the two results and explain why there is a difference. O The Energy Principle isn't valid for an inelastic collision. The internal energy of the block-bullet system has increased. O Some of the momentum is lost in an inelastic collision.
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