A broom balances at a point x from its upper end. When a weight of mass m is attached at its upper end, the point of balance shifts to x a. Find an expression for the weight of the broom b. What is the weight of the broom if m = 0.23 kg, x = 1.100 m and x 0.940 m? Hint: Recall that in the expression for the position of the center of mass, the integral represents a sum over all parts of the object in question. If another part is added then the sum is replaced by the same sum plus an extra term consisting of and integral over the added volume. If the extra part is discrete that can be modeled as a point mass, then the extra term will consist of the mass of the object multiplied by its position F dm becomes: Ie M orig orig mextra (M ons extra orig or, for an extra part that can be treated as a point mass F'dmrextra Mextra (M onis +mestra orig

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Chapter1: Units, Trigonometry. And Vectors
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A broom balances at a point x from its upper end. When a weight of mass m is attached
at its upper end, the point of balance shifts to x
a. Find an expression for the weight of the broom
b. What is the weight of the broom if m = 0.23 kg, x = 1.100 m and x 0.940 m?
Hint: Recall that in the expression for the position of the center of mass, the
integral represents a sum over all parts of the object in question. If another part is
added then the sum is replaced by the same sum plus an extra term consisting of
and integral over the added volume. If the extra part is discrete that can be
modeled as a point mass, then the extra term will consist of the mass of the object
multiplied by its position
F dm becomes:
Ie
M
orig orig
mextra
(M ons
extra
orig
or, for an extra part that can be treated as a point mass
F'dmrextra Mextra
(M onis
+mestra
orig
Transcribed Image Text:A broom balances at a point x from its upper end. When a weight of mass m is attached at its upper end, the point of balance shifts to x a. Find an expression for the weight of the broom b. What is the weight of the broom if m = 0.23 kg, x = 1.100 m and x 0.940 m? Hint: Recall that in the expression for the position of the center of mass, the integral represents a sum over all parts of the object in question. If another part is added then the sum is replaced by the same sum plus an extra term consisting of and integral over the added volume. If the extra part is discrete that can be modeled as a point mass, then the extra term will consist of the mass of the object multiplied by its position F dm becomes: Ie M orig orig mextra (M ons extra orig or, for an extra part that can be treated as a point mass F'dmrextra Mextra (M onis +mestra orig
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