A boy with mass m = 35 kg stands on a small stationary (at rest) merry-go- round near the edge of the merry-go-round. The total moment of inertia of the system of merry-go-round with the boy on it about the center is I = 231 kg · m? 1.8 m) jumps off the merry-go-round in a tangential direction with a linear speed of v, = 2.5 m/s. . The boy at the edge of the merry-go-round (radius R What is the angular velocity of the merry-go-round after the boy leaves it? (in units of rad/s. The +k direction is defined as out of the page.) Right before Wf Right after Pick the correct answer -1.34 Ê 2.78 k -0.46 k 1.34 k None of these are correct Let me look at the instructions 0.46

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Chapter11: Angular Momentum
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A boy with mass m =
35 kg stands on a small stationary (at rest) merry-go-
round near the edge of the merry-go-round. The total moment of inertia of the
system of merry-go-round with the boy on it about the center is I = 231 kg · m?
. The boy at the edge of the merry-go-round (radius R
merry-go-round in a tangential direction with a linear speed of Vb
1.8 m) jumps off the
2.5 m/s.
What is the angular velocity of the merry-go-round after the boy leaves it? (in
units of rad/s. The +k direction is defined as out of the page.)
wf
Right before
Right after
Pick the correct answer
-1.34 k
2.78 k
-0.46 k
1.34 k
None of these are correct
Let me look at the instructions
0.46 k
Transcribed Image Text:A boy with mass m = 35 kg stands on a small stationary (at rest) merry-go- round near the edge of the merry-go-round. The total moment of inertia of the system of merry-go-round with the boy on it about the center is I = 231 kg · m? . The boy at the edge of the merry-go-round (radius R merry-go-round in a tangential direction with a linear speed of Vb 1.8 m) jumps off the 2.5 m/s. What is the angular velocity of the merry-go-round after the boy leaves it? (in units of rad/s. The +k direction is defined as out of the page.) wf Right before Right after Pick the correct answer -1.34 k 2.78 k -0.46 k 1.34 k None of these are correct Let me look at the instructions 0.46 k
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