Here, we are supposed to find the deflection equations, we had done this problem with previous information the moment equations and the reaction forces (I have attached a picture of the solution), but now we have to expand on it... Boro do Norcemente ENGR 323-Mechanics IIHOMEWORK #6Deew 13A boy with a mass of 60 kg is standing on a diving board as shown below. The length from A-B is 0.6mand the length from B-C is 1.5m. Determine equations for the shear force and bending moment in the boardas a function of the distance from point A. You may disregard self-weight of the diving board.588 NProblem 6.1A0B0.6mA-BΣ Fy=0= + Ay - Vx1.5m0 < x < 0.6m1Vfor B-CΣ Fy=0= + Ay + By - VxX0.6 m < x < 2.1.AsoEMA↑Aтвуso By = 2,058 NWeightByΣ F₁₂ =0 = + Ay + 2,058 N -588 NAny(0.6m) -588N (2.1m) = 0B1131,470 N now Mx = -1,470 xSt. SmyAyByso - 1470N+ 2,058 N-VxBut for my My: -1,470x + 2,058 (X-0.6) + MxMy = 588 x + Cplug bounds.so V/x = 588Nso Ay = -1,470NA40.6Mx = + 1, 470x-2,058x + 1,235 +CMy = -588x +1,235 NmB(x -0.6)Xone optionto do stfCover Letter Problem 10.1A boy with a mass of 60 kg is standing on a wooden (E = 10 GPa) diving board as shown. The cross-section of the diving board is 40mm x 300mm. If the length AB is 0.6m and the length BC is 1.5mdetermine the maximum deflection in the diving board when the boy is standing at the end of the board.You may neglect the self-weight of the board in your analysis.You may appropriately reference previously completed work similar to this problem. Furthermore, you mayuse analysis software to check your final result, however all work leading up to the solution by method ofdouble integration should be shown.AB

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Elements Of Electromagnetics

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Here, we are supposed to find the deflection equations, we had done this problem with previous information the moment equations and the reaction forces (I have attached a picture of the solution), but now we have to expand on it...

Boro do Norcemente ENGR 323-Mechanics II
HOMEWORK #6
Deew 13
A boy with a mass of 60 kg is standing on a diving board as shown below. The length from A-B is 0.6m
and the length from B-C is 1.5m. Determine equations for the shear force and bending moment in the board
as a function of the distance from point A. You may disregard self-weight of the diving board.
588 N
Problem 6.1
A
0
B
0.6m
A-B
Σ Fy=0= + Ay - Vx
1.5m
0 < x < 0.6m
1
V
for B-C
Σ Fy=0= + Ay + By - Vx
X
0.6 m < x < 2.1.
A
so
EM
A
↑
A
тву
so By = 2,058 N
Weight
By
Σ F₁₂ =0 = + Ay + 2,058 N -588 N
Any
(0.6m) -588N (2.1m) = 0
B
113
1,470 N now Mx = -1,470 x
St. Smy
Ay
By
so - 1470N+ 2,058 N-Vx
But for my My: -1,470x + 2,058 (X-0.6) + Mx
My = 588 x + C
plug bounds.
so V/x = 588N
so Ay = -1,470N
A
4
0.6
Mx = + 1, 470x-2,058x + 1,235 +C
My = -588x +1,235 Nm
B
(x -0.6)
X
one option
to do st
f
Cover Letter

Problem 10.1
A boy with a mass of 60 kg is standing on a wooden (E = 10 GPa) diving board as shown. The cross-
section of the diving board is 40mm x 300mm. If the length AB is 0.6m and the length BC is 1.5m
determine the maximum deflection in the diving board when the boy is standing at the end of the board.
You may neglect the self-weight of the board in your analysis.
You may appropriately reference previously completed work similar to this problem. Furthermore, you may
use analysis software to check your final result, however all work leading up to the solution by method of
double integration should be shown.
A
B

Expert Solution

Step 1 Given

The length AB is $0.6 m$

The length BC is $1.5 m$

The E of the wooden board is $10 G P a$

The cross-section of the diving board is $40 m m \times 300 m m$

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