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art b) Bending moment by real forces_1 Let the origin of the horizontal coordinate x be at the support A and the positive x-axis points to the right. The bending moment caused by the real forces as a function of x can be discribed as For 0≤ x ≤9 m, (please use units kN.m for bending moment) (Use * for multiplication and for exponentiation. For exmple, 2x + ² can be written as 2*x+x^2)

art b) Bending moment by real forces_1 Let the origin of the horizontal coordinate x be at the support A and the positive x-axis points to the right. The bending moment caused by the real forces as a function of x can be discribed as For 0≤ x ≤9 m, (please use units kN.m for bending moment) (Use * for multiplication and for exponentiation. For exmple, 2x + ² can be written as 2*x+x^2)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Part b) Bending moment by real forces_1 Let the origin of the horizontal coordinate x be at the support A and the positive x-axis points to the right. The bending moment caused by the real forces as a function of x can be discribed as For 0≤x≤9 m, (please use units kN.m for bending moment) (Use * for multiplication and ^ for exponentiation. For exmple, 2+² can be written as 2*x+x^2)
Transcribed Image Text:Part b) Bending moment by real forces_1 Let the origin of the horizontal coordinate x be at the support A and the positive x-axis points to the right. The bending moment caused by the real forces as a function of x can be discribed as For 0≤x≤9 m, (please use units kN.m for bending moment) (Use * for multiplication and ^ for exponentiation. For exmple, 2+² can be written as 2*x+x^2)
For the beam shown in Fig.Q4, use the principle of virtual work to determine (1) the vertical deflection at Point C, and (2) the rotation at the right-hand bearing (Point B). The Young's modulus of the material is E = 200 GPa. The cantilever beam has a circular cross section with the second moment of area / = 30 x 106 m². The beam is under a uniformly distributed load q=15 kN/m at the AB span and a point force P=27 kN at Point C. The length of AB span is L=9 m and the length of BC span is L₁ =3.6 m. (In this question, we assume (1) the positive direction of a vertical force points upwards; (2) the positive direction of a horizontal force points to the right; and (3) the postive direction of an applied moment is clockwise.) L BA L₁ Part a) Reactions The vertical reaction force at support A can be calculated as The vertical reaction force at support B can be calculated as The horizontal reaction force at support A can be calculated as KN KN KN р
Transcribed Image Text:For the beam shown in Fig.Q4, use the principle of virtual work to determine (1) the vertical deflection at Point C, and (2) the rotation at the right-hand bearing (Point B). The Young's modulus of the material is E = 200 GPa. The cantilever beam has a circular cross section with the second moment of area / = 30 x 106 m². The beam is under a uniformly distributed load q=15 kN/m at the AB span and a point force P=27 kN at Point C. The length of AB span is L=9 m and the length of BC span is L₁ =3.6 m. (In this question, we assume (1) the positive direction of a vertical force points upwards; (2) the positive direction of a horizontal force points to the right; and (3) the postive direction of an applied moment is clockwise.) L BA L₁ Part a) Reactions The vertical reaction force at support A can be calculated as The vertical reaction force at support B can be calculated as The horizontal reaction force at support A can be calculated as KN KN KN р
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