A box with a mass of 8 kg is resting on a horizontal surface. If the coefficient of static friction between the box and the surface is 0.5, what is the minimum force required to start moving the box? (Assume) In Newton unit ○ 19.6 ○ 39.2 ○ 17.6 ○ 45.2
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I need help with this problem and an explanation for the solution described below. (University Physics 1: Newton's Laws (Dynamics))
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- A 50.7 kg box is resting on a horizontal floor. A force of 317.1 N directed at an angle of 34.1° below the horizontal is applied to the box. The coefficient of static friction between the box and the surface is 0.5, and the coefficient of kinetic friction is 0.2. The force of friction on the box is:A 5.0kg crate is tasting on a horizontal plank. The coefficient of static friction is 0.50. You raise one end of the plank slowly. What is the maximum angle (with horizontal) you can go without the crate sliding down the incline?The coefficient of kinetic friction between a box and the floor is μk = 0.14 and the coefficient of static friction is μs = 2.0μk. Calculate the ratio of static to kinetic friction force if m = 8 kg.
- Suppose a 25.0 kg block rests on a horizontal plane, and the static friction coefficient between the surfaces is 0.220. (a) What is the maximum allowable static frictional force that could act on the block? (b) What is the actual static frictional force acting on the block if a 25.0 N external force acts horizontally? Assume g = 9.80 m/s2.A small box is held in place against a rough wall by someone pushing on it with a force directed upward at an angle of 260 above the horizontal. The coefficient of static and kinetic friction between the box and the wall are 0.40 and 0.30, respectively. The box slides down unless the applied force has a magnitude of 13 N. What is the mass of the box?A 45 kg box is at rest at one end of a 2 meter board. That end of the board is slowly raised at an incline until the box starts to slide. At that point, the angle is at 34 degrees. The coefficient of kinetic friction is 0.50N. Please help me calculate the coefficient of static friction between both the box and the board?
- 1. A block is placed on a wooden plank, which is initially horizontal. One end of the plank is slowly raised to make it more and more inclined, and for a while the block stays in place on the plank and doesn't slide due to static friction. Finally, when the plank reaches an incline of 56.3o above horizontal, the block begins to slide. What is the coefficient of static friction between the block and the plank? 1.50 1.00 2.00 0.500 2. Continuing the story from the previous question... after the block begins sliding down the incline at 56.3o, you measure its acceleration down the plank as 7.42 m/s2. What is the coefficient of kinetic friction between the block and the plank? 0.136 0.241 0.190 0.562The coefficient of kinetic friction between a box and the floor is u, = 0.16 and the coefficient of static friction is u, = 2.0µ. (a) Calculate the ratio of static to kinetic friction force if m = 9 kg. (b) Will the ratio change if the value of m is changed but u, still equals 2.0µ? Yes NoA woman holds a book by placing it between her hands such that she presses at right angles to the front and back covers. The book has a mass of m = 1.7 kg and the coefficient of static friction between her hand and the book is μs = 0.59. Force minimum?
- You can hold your 2.5 kg textbook against the wall, preventing it from slipping down, if you press your hand against it horizontally. Suppose the coefficient of static friction between the book and the wall is 0.50, and there is no friction between your hand and the book. What minimum force do you need to apply to keep the book from slipping down?7. Suppose a 25.0 kg block rests on a horizontal plane, and the static friction coefficient between the surfaces is 0.220. (a) What is the maximum allowable static frictional force that could act on the block? (b) What is the actual static frictional force acting on the block if a 25.0 N external force acts horizontally? Assume g 9.80 m/s.The 121-lb force P is applied to the 250-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate. The friction force is positive if to the right, negative if to the left. Assume μ = 0.45, μk = 0.36. Answer: F= i lb