A box of a certain mass is attached to a spring of spring constant 7.0 N/m and experience simple harmonic motion with an amplitude of 0.2 m. When the position of a box is at 0.4A its speed is measured to be + 0.25 m/s. (Hint: x(t) = Asinwt). Calculate the maximum acceleration of the box.

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A box of a certain mass is attached to
a spring of spring constant 7.0 N/m
and experience simple harmonic
motion with an amplitude of 0.2 m.
When the position of a box is at 0.4A
its speed is measured to be + 0.25
m/s. (Hint: x(t)
Asinwt). Calculate
the maximum acceleration of the box.
А.
0.37 m/s2
В.
3.66 m/s2
O C.
С.
1.19 m/s2
טך
Transcribed Image Text:A box of a certain mass is attached to a spring of spring constant 7.0 N/m and experience simple harmonic motion with an amplitude of 0.2 m. When the position of a box is at 0.4A its speed is measured to be + 0.25 m/s. (Hint: x(t) Asinwt). Calculate the maximum acceleration of the box. А. 0.37 m/s2 В. 3.66 m/s2 O C. С. 1.19 m/s2 טך
Expert Solution
Step 1

The equation of position of the block attached to the spring which experiences simple harmonic motion is given as is given as

x(t) = Asin(ωt) .........................(1)where,x(t) is the position of the block at any time tA is the amplitude of the blockω is the angular frequency

Here, it is given that

spring constant, k = 7 N/m

amplitude of the box, A = 0.2 m

speed of the box at x = 0.4 A is v = 0.25 m/s

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