A box of 8 cellphones contains two yellow cellphones and six green cellphones. Complete parts (a) through (d) below. (... a. If two cellphones are randomly selected from the box without replacement, what is the probability that both cellphones selected will be green? P(both green) = (Round to four decimal places as needed.) b. If two cellphones are randomly selected from the box without replacement, what is the probability there will be one green cellphone and one yellow cellphone selected? P(1 green and 1 yellow) = (Round to four decimal places as needed.) c. If three cellphones are selected with replacement (the first cellphone is returned to the box after it is selected), what is the probability that all three will be yellow? P(three yellow) = (Round to four decimal places as needed.) d. If you were sampling with replacement (the first cellphone is returned to the box aftor it is selected), what would be the answers to (a) and (b)? P(both green) = (Round to four decimal places as needed.) (Round to four decimal places as needed.) P(1 green and 1 yellow) =

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