blue balls and 3 green balls. Two balls are drawn consecutively without replacement. assume that the random variable Y defines the number of blue balls?1.Construct a probability distribution for Y. 2.what is the mean of the distribution?Interpret the result. 3.Compute the variance and standard deviation of the distribution.

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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A box contains 4 blue balls and 3 green balls. Two balls are drawn consecutively without replacement. assume that the random variable Y defines the number of blue balls?1.Construct a probability distribution for Y. 2.what is the mean of the distribution?Interpret the result. 3.Compute the variance and standard deviation of the distribution.
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As per the bartleby guidelines for more than two parts only two has to be solved. Please upload the other parts separately.

The number of blue balls in the box is 4 and the number of green balls in the box is 3.

It is given that two balls are drawn consecutively without replacement , 

The probabilities of the events are :

Events  Probability 
GG 37×26=17
GB 37×46=27
BG 47×36=27
BB 47×36=27

 

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