5 And 6 please ### Experiment Questions for Educational Purposes3. **Question**: What is the purpose of adding the H₂SO₄ to the reaction mixture?4. **Question**: Explain what causes the color change that occurs at the endpoint in this experiment.5. **Question**: A bottle is labeled 0.26 M KMnO₄. The KMnO₄ will be used in the same reaction as took place in this experiment. What volume of the solution, approximately, must be used to make 750 mL of approximately 0.18 M KMnO₄ solution?6. **Question**: In a student's experiment, the KNOWN H₂C₂O₄ had a concentration of 0.350 M. A 10.00 mL sample of the H₂C₂O₄ required 34.20 mL of a KMnO₄ solution. What is the concentration of the KMnO₄ solution?7. **Question**: What is used to clean the glassware at the end of this experiment? Why is it needed?No graphs or diagrams are present in this image.

Since you have posted multiple questions, we are entitled to answer the first only. 5) Given : Concentration of stock KMnO4 solution = 0.26 M Concentration of final KMnO4 solution = 0.18 M And volume of final solution = 750 mLSince to decrease the concentration of stock KMnO4 solution to produce final solution, water will be added in some volume of stock solution. And since only water is being added, hence the moles of KMnO4 in initial stock solution and final solution will be same. Since moles = concentration X volume of solution => Concentration of stock KMnO4 solution X volume of stock solution required = concentration of final KMnO4 solution X volume of final solution Hence substituting the values we get, => 0.26 X volume of stock solution required = 0.18 X 750 => volume of stock solution required = 519.2 mL approx. Hence the answer is 519.2 mL approx.