A boomerang is thrown to the air with a velocity of 25.0 m/s at an angle of 45.0° from the horizontal. The boomerang has a mass of 0.5 kg and rotates at 10.0 rev/s. The moment of inertia of the boomerang is given as: I = mL where L-0.5 m. a)What is the total energy of the boomerang as it leaves the hand of the thrower (neglecting air resistance)? ( Select ] b)How high would the boomerang go (from the hand), neglecting air resistance? (Select]

A boomerang is thrown to the air with a velocity of 25.0 m/s at an angle of 45.0° from the horizontal. The boomerang has a mass of 0.5 kg and rotates at 10.0 rev/s. The moment of inertia of the boomerang is given as: I = mL where L-0.5 m. a)What is the total energy of the boomerang as it leaves the hand of the thrower (neglecting air resistance)? ( Select ] b)How high would the boomerang go (from the hand), neglecting air resistance? (Select]