A body, of mass m, falls from rest at a height y,. If the drag (resisting) force of air isassumed to be proportional to the instantaneous velocity v of the body. Use k as theproportionality constant and take (y = 0) at ground level.(1) Find the height of the body y as a function of its velocity v.(2) Find the height of the body y as a function of time t.(3) Assuming that g = 9.81 m/s², m = 1 kg, y, = 2000 m and k = 0.01, calculate theheight of the body 20 seconds after it starts falling.

Answered: Image /qna-images/answer/6e73a3e9-6a75-4c28-a350-55d28ed97edd.jpg

Answered: A body, of mass m, falls from rest at a…

Similar questions

A 1.57 kg mass is sliding across a horizontal surface an initial velocity of 12.9 m/s i. If the object then comes to a stop over a time of 4.23 seconds, what must the coefficient of kinetic be? Assume that only friction, the normal force, and the force due to gravity are acting on the mass. Enter a number rounded to 3 decimal places.
A monkey pushes a box of mass 25 kg in a straight line across a rough floor. The applied force F has magnitude 85 N and acts downward at an angle 0 = 10° with respect to the horizontal, as shown below. The box is initially at rest at the position x/ a). Find the coefficient of friction between the box and the floor. and it has speed v2 = 0.55 m/s at position x2 = 3.50 m. 0 m, b). What is the net work done? c). How much work (magnitude and sign) is done by the friction force? m Hint: this q involves constant acceleration, Newton's laws, work
A 6 kg block is sliding down on a rough inclined surface that makes θ = 30° with respect to the horizontal. The kinetic frictional coefficient between the block and the surface is 0.19. Find the acceleration a of the block.
A semi is traveling down the highway at a velocity of v = 27.5 m/s. The driver observes a wreck ahead, locks his brakes, and begins to slide. The truck has mass m and a coefficient of kinetic friction between the tires and the road of μk = 0.16. Write an expression for the sum of the forces in the x-direction for the truck while braking? Using the results from Part (a), input an expression for the truck's acceleration, at, while breaking? What is the magnitude of the acceleration in m/s2? How far does the truck travel, d in meters, before stopping?
A box, initially at rest, is pushed up a ramp that makes an angle of 15◦ with the horizontal as shown in the diagram. The magnitude of the pushing force is 8m newtons, where m is the mass of the box in kilograms. The force is in a direction parallel to and up the ramp. The coefficient of sliding friction between the box and the ramp is 0.25. Model the box as a particle and take the magnitude of the acceleration due to gravity to be g = 9.8 m s−2 . Express the four forces in component form in terms of unknown magnitudes where appropriate and find an expression for the resultant force acting on the box. Hence find the magnitude of the acceleration of the box, in m s−2
A block of mass 14.2 kg is sliding at an initial velocity of 7.65 m/s in the positive x-direction. The surface has a coefficient of kinetic friction of 0.193. (Indicate the direction with the signs of your answers.) It gives a hint as follows: (a) Find the normal force and apply the relation between the normal force and the kinetic friction force. (b) Apply the x-component of Newton's second law. (c) Solve for the displacement using a kinematic equation.
A soldier jumps from a plane and opens his parachute when his velocity reaches the terminal velocity Vr. The parachute shows him down to his landing velocity of Vr. After the parachute is deployed, the air resistance force is proportional to the velocity squared, i.e., F = kV², where k is resistance coefficient. The soldier, his parachute, and his gear have a total mass of m. (a) Show that k = mg/V; (b) Develop a relation for the soldier's velocity after he opens the parachute at time 1 = 0. Parachute Figure Q5
Figure 1 В А Three blocks, labeled A, B, and C, are connected by essentially massless strings that run over essentially massless and frictionless pulleys (as shown in Figure A above). Block A hangs straight down. The string from block A connects to block B which is sliding up and to the left along an inclined plane. The plane is inclined at an angle of theta = 0 = 52 degrees away from vertical. The coefficient of kinetic friction between block B and the plane is 0.38. Block B is connected by a different string to block C which hangs straight down. Block A has a mass of 4.1 kg. Block B has a mass of 3.7 kg. Block C has a mass of 2.5 kg. Block A is moving down and block C is moving up (the strings do not stretch). The only significant forces acting on the blocks are friction acting on block B, normal forces, tension forces, and gravity (with g = 9.81 m/s²). Calculate the %3D acceleration (in units of meters per second squared) of block A. For block A, a downward acceleration is…