A body of mass (0.5 kg) contacts a fixed spring of (20 N/m) and lets it oscillate horizontally and freely. If the body moves a distance (5 cm) from its equilibrium position, the body's kinetic energy is: * 0.5 J Not what was mentioned 0.05 J
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- A pendulum of mass 90 gm and length 60 cm is left to swing from an initial angle of 40 degrees, and seen to raise up to an angle of 38 degrees when it reaches the other side. How much energy did the pendulum lose? Why is there a loss of energy?One end of a horizontal spring with k=80N/m is fixed on the wall. A 5kg block is moving at 2m/s when it touches on the free end of a spring. Find the maximum compression of spring Δ: a) if the floor is frictionless ... Δa=...b) if there is kinetic friction with magnitude 10N between block and the floor..... Δb=...c) the amount of thermal energy produced in case (a).. ΔEth-a=.... and (b)... ΔEth-b=.......A mass of 1.2kg is attached to a spring with a constant 12N/m. it is then displaced to a maximum point of 2m. How much time does it take for the block to travel to the point x=1.5m? answer in seconds
- hass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 9 inches below the equilibrium position. (a) Find the position x of the mass at the timest= 1/12, 1/8, 1/6, 11/4, and 91/32 s. (Use g = 32 ft/s? for the acceleration due to gravity.) x(n/12) = ft x(n/8) = ft x(п/6) — ft x(п/4) — ft x(9n/32) ft (b) What is the velocity of the mass when t = 3t/16 s? ft/s In which direction is the mass heading at this instant? O downward O upward (c) At what times does the mass pass through the equilibrium position? п 3D 0, 1, 2, ..KE of a simple pendulum Due in 6 hours, 20 minutes 70 60 50 40 30 20 10 -100 -50 50 100 e (mrad) In the figure above, the kinetic energy of a simple pendulum is plotted against its angle 0 from the vertical. If the mass of the pendulum bob is 1.14 kg, what is the length of the pendulum? 0.537 m Submit Answer Incorrect. Tries 9/10 Previous Tries Kinetic Energy (mJ)One end of a spring is attached to a fixed wall while a 0.25-kg block is attached to the other movable end. The spring is stretched 0.7-m horizontally, then released from rest. Calculate its speed when it goes back to equilibrium if the spring's force constant is k = 5 N/m.