Answered: A body of mass (0.5 kg) contacts a… | bartleby

Related questions

Question

A body of mass (0.5 kg) contacts a fixed spring of (20 N/m) and lets it oscillate horizontally and
freely. If the body moves a distance (5 cm) from its equilibrium position, the body's kinetic
energy is:
*
0.5 J
Not what was mentioned
0.05 J
5 J

Expert Solution

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

Asap
A force of 500 N is used to stretch a spring with a 0.5 kg to 350 mm. The frequency of the oscillator is computed as
Problem 1. Energy Terms Determine the potential energy of the pendulum shown below. Note: The potential en- ergy should be 0 when 0 = 0, mgL when 0=1, and 2mgL when 0 = 1. /////// 8 m Q Search 99+ H
Can I have some help with this question please for physics
One end of a spring is attached to a fixed wall while a 0.13-kg block is attached to the other movable end. The spring is stretched 0.8-m horizontally. then released from rest. Calculate its speed when itgoes back to equilibrium if the spring's force constant is k = 5 N/m.
Please answer and solve the question correctly. Thank you!
Eecrgy: Jouks E- 0.2 Jonles 0,20 0.15 0.10 0.05 A plot of the energy of a mass-spring system * m= 0.30kg. where: X - 0 025 m Directions From the above figure, determine for the following when Et = 0.2J, x = 0.025 & M = 0.30 kg: 1. The potential energy = joules 2. The kinetic energy = joules 3. The spring constant = N/m 4. The speed of the particle = m/sec. 5. The amplitude of the motion = meter 6. The maximum velocity = m/sec 7. The spring force = N 8. The equation of the displacement ob00- 010'0- 0,0+ 0,020+
A pendulum of mass 90 gm and length 60 cm is left to swing from an initial angle of 40 degrees, and seen to raise up to an angle of 38 degrees when it reaches the other side. How much energy did the pendulum lose? Why is there a loss of energy?
One end of a horizontal spring with k=80N/m is fixed on the wall. A 5kg block is moving at 2m/s when it touches on the free end of a spring. Find the maximum compression of spring Δ: a) if the floor is frictionless ... Δa=...b) if there is kinetic friction with magnitude 10N between block and the floor..... Δb=...c) the amount of thermal energy produced in case (a).. ΔEth-a=.... and (b)... ΔEth-b=.......
A mass of 1.2kg is attached to a spring with a constant 12N/m. it is then displaced to a maximum point of 2m. How much time does it take for the block to travel to the point x=1.5m? answer in seconds
hass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 9 inches below the equilibrium position. (a) Find the position x of the mass at the timest= 1/12, 1/8, 1/6, 11/4, and 91/32 s. (Use g = 32 ft/s? for the acceleration due to gravity.) x(n/12) = ft x(n/8) = ft x(п/6) — ft x(п/4) — ft x(9n/32) ft (b) What is the velocity of the mass when t = 3t/16 s? ft/s In which direction is the mass heading at this instant? O downward O upward (c) At what times does the mass pass through the equilibrium position? п 3D 0, 1, 2, ..
An object starts from rest and moves a distance d due to the presence of a net force F_net. If the net force is doubled (F'_net = 2F_net) while keeping the same distance d, then which of the statements below cannot be true? Its final kinetic energy is doubled Its acceleration is doubled O The net work is doubled OIts final speed is doubled For a mass-spring system that undergoes a simple harmonic

SEE MORE QUESTIONS