2] One end of a horizontal spring with k=80N/m is fixed on the wall. A 5kg block is moving at 2m/s when it touches on the free end of a spring. Find the maximum compression of spring A: a) if the floor is frictionless ... Aa=... b) if there is kinetic friction with magnitude 10N between block and the floor... Ap=... c) the amount of thermal energy produced in case (a).. AEth-a=.... and (b)... AEth-b=.. v=2m/s State "1" k------ a ------ State "2" k--- a .-- State "3"

Q: Tests on a spring showed that 1000-N of force was required to compress the spring 0.5-m. The spring…

A: Given data: The force applied is F=1000 N. The compression in spring is x=0.5 m. The mass of ball…

Q: Suppose the initial speed of the block is 1.17m/s, but its mass can be varied. What mass is required…

A: According to the conservation of energy, to find the required mass needed for the compression of the…

Q: CALC Consider a spring that does not obey Hooke's law very faithfully. One end of the spring is…

A: We are aware that the force Fx=kx-bx2+cx3 operating along the x-axis with an x-component.K has a…

Q: A block of mass 0.75 kg slides on a rough horizontal tabletop. It hits a spring and compresses it…

A: The given values are, m=0.75 kgx=5.7 cm=0.057 mk=100 N/mμk=0.25

Q: A 0.280-kg block along a horizontal track has a speed of 1.70 m/s immediately before colliding with…

A: (a). using conservation of energy, the initial kinetic energy is equal to the final spring energy.…

Q: A M =7 kg mass is moving at vo = 8 m/s along a frictionless, horizontal = 800 N/m that is attached…

A:

Q: A 2.4 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it…

A: Using energy conservation  KE=PE stored in spring

Q: One end of a spring is attached to a fixed wall while a 0.11-kg block is attached to the other…

A: Given Mass of block is m=0.11 kg Spring constant is k= 3 N/m Stretched distance is x=0.9 m

Q: spring is on a horizontal table and a mass of 10 kg approaches it at a speed of 5 m/sec; it is 0.5 m…

A:

Q: When a 0.36-kg block is suspended on a vertical spring, it causes it to stretch 2.80 cm. If the…

A: Given, mass of block, m = 0.36 kg x = 0.028 m

Q: Iace with d speed of 1.8 m/s when it encounters a spring. (a) Determine the force constant (in N/m)…

A: Mass "m" = 2.6 kg . initial velocity "u" = 1.8m/s .

Q: A block of mass m is attached to the end of a horizontal massless spring (spring con- stant k),…

A: Mass of block = m Spring constant = k Initial displacement = xo Initial speed = vo

Q: a box of mass  m = 9.20 kg is sliding across a horizontal frictionless surface with an initial speed…

A: According to the law of conservation of energy , energy can neither be created nor destroyed but can…

Q: A frictionless spring with a 2-kg mass can be held stretched 1.6 meters beyond its natural length by…

A: See below

Q: The length of a spring increases by 6.00 cm from its relaxed length when a mass of 1.40 kg is…

A: Given:Displacement = change in the length of the spring = 6 cmMass = 1.4 kg

Q: A horizontal spring-mass system oscillates on a frictionless table. If the ratio of the mass to the…

A:

Q: A block of mass m = 1.50 kg is dropped from height h = 46.0 cm onto a spring of spring constant k =…

A:

Q: A block of mass 3.60 kg is placed against a horizontal spring of constant k = 825 N/m and pushed so…

A:

Q: A vertical spring with a spring constant of 490 N/m is mounted on the floor. From directly above the…

A:

Q: A block of mass 3.20 kg is placed against a horizontal spring of constant k = 865 N/m and pushed so…

A:

Q: As shown in the figure below, a box of mass m = 6.00 kg is sliding across a horizontal frictionless…

A:

Q: A spring-loaded dart gun is used to shoot a dart straight up into the air. When fully compressed,…

A: Solution

Q: A spring of spring constant k 625 N/m rests on a horizontal frictionless surface. A 0.25 kg object…

A: Given that, Mass = 0.25 kg Spring constant = 625 N/m ∆L=0.5 m

Q: A 6.00 x 105 kg subway train is brought to a stop from a speed of 0.500 m/s in 0.500 m by a large…

A:

Q: An object with mass m is suspended at rest a spring with a spring constant of 200 N/m. The length of…

A: Energy stored in spring = (1/2)kx2  Where  k = spring constant         x= stretched lengh

Q: If a spring is stretched a distance of 24 m, it stores 960 J of elastic potential energy. What is…

A: Given: The extension in the spring is 24 m. The potential energy of the spring is 960 J.

Q: A 0.300-kg block along a horizontal track has a speed of 1.30 m/s immediately before colliding with…

A: a)Change in kinetic energy of block is the equal to the potential energy of compressed spring.

Q: A 15kg box is placed on top of a spring with a natural length of 30cm. The weight of the box…

A:

Q: A block of mass mm is attached to the end of a spring (spring stiffness constant k), (Figure 1). The…

A: Mass of block = m stiffness constant = k initial displacement = xoinitial velocity = vo

Q: 7. A 7.5-lb collar is released from rest in the position shown, slides down the inclined rod, and…

A:

Q: ne end of a spring is attached to a fixed wall while a 0.44-kg block is attached to the other…

A: Given: mass of block m = 0.44 kg stretched distance x = 0.8 m force constant of spring k=4 N/m

Q: 10. A 1.45-kg block is pushed against a vertical wall by means of a spring (k = 850 N/m). The…

A: Given that m= 1.45 kg k= 850 N/m Coefficient of friction=0.56 Minimum compression in spring x=?

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.