A body about a quarter of a pound (m) falls down from a height (h) of 300 due to gravity. Due to the viscosity of the air, there is a resistance to its movement, whose coefficient (k) is equal to one tenth of a pound-second per foot. Get the time it takes to hit the ground with 2D accuracy. The acceleration of gravity is 32.17 feet per square second. m²g (1- kt mg y(t) = h – t + е т %3D k k2

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A body about a quarter of a pound (m) falls down from a height (h) of 300 due to gravity. Due to the viscosity of the air, there is a resistance to its movement, whose coefficient (k) is equal to one tenth of a pound-second per foot. Get the time it takes to hit the ground with 2D accuracy. The acceleration of gravity is 32.17 feet per square second.
y(t)=h-mg/k t+(m^2 g)/k^2 (1-e^(-kt/m))

A body about a quarter of a pound (m) falls down from a
height (h) of 300 due to gravity. Due to the viscosity of the
air, there is a resistance to its movement, whose coefficient
(k) is equal to one tenth of a pound-second per foot. Get
the time it takes to hit the ground with 2D accuracy.
The
acceleration of gravity is 32.17 feet per square second.
2
kt
mg
y(t) = h –
k
– em
- (1 — е т
-
k2
Transcribed Image Text:A body about a quarter of a pound (m) falls down from a height (h) of 300 due to gravity. Due to the viscosity of the air, there is a resistance to its movement, whose coefficient (k) is equal to one tenth of a pound-second per foot. Get the time it takes to hit the ground with 2D accuracy. The acceleration of gravity is 32.17 feet per square second. 2 kt mg y(t) = h – k – em - (1 — е т - k2
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