A block on a frictionless table is connected as shown in (Figure 1) to two springs having spring constants ky and ky Figure m K₂ 1 of 1 Y Part A Show that the block's oscillation frequency is given by 1=√√√R+R where fi and f₂ are the frequencies at which it would oscillate if attached to spring 1 or spring 2 alone. There are two restoring forces on the block. If the blocks displacement az is positive, both restoring forces one pushing, the other pulling Care directed to the left and have negative values: (Foet) (Fap 1) + (F2)z-k₁z²kya² = (-k₂+k₂)² = k₁² Owhere kefky + ky is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as if the block were attached to a single spring with spring constant keff The frequency of the blocks, therefore, is = √R R 1 kett f= f = 2x V m √ = 2T √ m - There are two restoring forces on the block If the blocks displacement z is positive, both restoring forces one pushing, the other pulling are directed to the left and have negative values i (Fuet) (Fup 1) + (Fp 2)a-ka-ka-(-k₁+k₂)α-k where kettky + ky is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as if the block were attached to a single spring with spring constant kett The frequency of the blocks, therefore, is Keff 1 ky + ky 2 √R+1} m 1 2T V There are two restoring forces on the block. If the blocks displacement z is positive, both restoring forces one pushing, the other pulling are directed to the left and have negative values 1 katt f = √ = 27 776 (Fot) (Fup 1) + (F2) -kk-(-k₁+k₂)²-- where kefkyky is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as if the block were attached to a single spring with spring constant keff. The frequency of the blocks, therefore, is 1k₁+k VR+B F 1 Kett 1= 2√ m k₁+k₂ 771 There are two restoring forces on the block. If the blocks displacement a is positive, both restoring forces one pushing, the other pullingCare directed to the left and have negative values. - (Fact) (F1) + (F₁2)x= -²²²²-(kk) ²² where katky + ky is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as if the block were attached to a single spring with spring constant kett. The frequency of the blocks, therefore, is VRT 1 2m V = 172 Submit Request Answer k₁+k₂ 771 = +

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A block on a frictionless table is connected as shown in (Figure 1) to
two springs having spring constants ky and k
Figure
e
m
k₂
1 of 1
▼
Part A
Show that the block's oscillation frequency is given by
f=√√√√1²+12
where fi and f₂ are the frequencies at which it would oscillate if attached to spring 1 or spring 2 alone.
There are two restoring forces on the block. If the blocks displacement z is positive, both restoring forces one pushing, the other pullingCare directed to the
left and have negative values:
(Fnet)
(Fap 1)2 + (Fp2)z = -k₁z²k₂a² = (-k₂ + k₂)x² = -kuz²
Owhere keff = k₁+k₂ is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as
if the block were attached to a single spring with spring constant keff The frequency of the blocks, therefore, is
1 Kett
1
k₁+k₂
f = 2xVm= 2 V 771
There are two restoring forces on the block If the blocks displacement z is positive, both restoring forces one pushing, the other pulling are directed to the
left and have negative values.
(Fuet)-(Fap 1)2 + (Fap 2)₂ = -k₁-k₂-(-k₁+k₂)x= -keff
Owhere kefky + ky is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as
if the block were attached to a single spring with spring constant keff The frequency of the blocks, therefore, is
1
/k₁+k₂
2T V
771
There are two restoring forces on the block. If the blocks displacement z is positive, both restoring forces one pushing, the other pulling are directed to the
left and have negative values
1 keff
S=
J= 2√ m
(Fort)z (Fap 1)2 + (Ep 2)₂ = kxkx=(-k₁+k₂)² = -²
where keffk₁+k₂ is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as
if the block were attached to a single spring with spring constant keff. The frequency of the blocks, therefore, is
katt
774
VR+R
f = 1/² √ 1, k₁+k₂
=
2 V 772
m
1
Kett
f = 2√ m
2x
=
There are two restoring forces on the block. If the blocks displacement az is positive, both restoring forces one pushing, the other pulling are directed to the
left and have negative values.
(Fact) = (F 1)2 + (F2)x= k₁z²k²² - (-²+k²)² --K²2²
Submit
where keff
ki + ky is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as
if the block were attached to a single spring with spring constant koff. The frequency of the blocks, therefore, is
/f}+f}
Provide Feedback
1 k₁+k₂
2 V
771
-
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=
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9:43 PM
12/7/2022
Transcribed Image Text:A block on a frictionless table is connected as shown in (Figure 1) to two springs having spring constants ky and k Figure e m k₂ 1 of 1 ▼ Part A Show that the block's oscillation frequency is given by f=√√√√1²+12 where fi and f₂ are the frequencies at which it would oscillate if attached to spring 1 or spring 2 alone. There are two restoring forces on the block. If the blocks displacement z is positive, both restoring forces one pushing, the other pullingCare directed to the left and have negative values: (Fnet) (Fap 1)2 + (Fp2)z = -k₁z²k₂a² = (-k₂ + k₂)x² = -kuz² Owhere keff = k₁+k₂ is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as if the block were attached to a single spring with spring constant keff The frequency of the blocks, therefore, is 1 Kett 1 k₁+k₂ f = 2xVm= 2 V 771 There are two restoring forces on the block If the blocks displacement z is positive, both restoring forces one pushing, the other pulling are directed to the left and have negative values. (Fuet)-(Fap 1)2 + (Fap 2)₂ = -k₁-k₂-(-k₁+k₂)x= -keff Owhere kefky + ky is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as if the block were attached to a single spring with spring constant keff The frequency of the blocks, therefore, is 1 /k₁+k₂ 2T V 771 There are two restoring forces on the block. If the blocks displacement z is positive, both restoring forces one pushing, the other pulling are directed to the left and have negative values 1 keff S= J= 2√ m (Fort)z (Fap 1)2 + (Ep 2)₂ = kxkx=(-k₁+k₂)² = -² where keffk₁+k₂ is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as if the block were attached to a single spring with spring constant keff. The frequency of the blocks, therefore, is katt 774 VR+R f = 1/² √ 1, k₁+k₂ = 2 V 772 m 1 Kett f = 2√ m 2x = There are two restoring forces on the block. If the blocks displacement az is positive, both restoring forces one pushing, the other pulling are directed to the left and have negative values. (Fact) = (F 1)2 + (F2)x= k₁z²k²² - (-²+k²)² --K²2² Submit where keff ki + ky is the effective spring constant. This means the oscillatory motion of the block under the influence of the two springs will be the same as if the block were attached to a single spring with spring constant koff. The frequency of the blocks, therefore, is /f}+f} Provide Feedback 1 k₁+k₂ 2 V 771 - Request Answer Review | Constants = P Pearson Copyright 2022 Pearson Education Inc. All rights reserved | Terms of Use | Privacy Policy | Permissions Contact Us L Links a Am Next >> O 9:43 PM 12/7/2022
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