A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction us by measuring the critical angle e where slipping occurs. fr mg pin o

Elements Of Electromagnetics
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FILL IN THE BLANKS. A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction μs by measuring the critical angle θ where slipping occurs.

Solution
Just before slipping, we say that the block is still at rest, so the net force on the x-axis is:
EFx=mg
-f
Evaluating, we get:
f
= mg
But the frictional force is expressed as the product of coefficient and the normal force so.
Ps
= mg
For an inclined plane. The normal force is
n=mg
Then,
Hs=mg
cos(e)
so:
Ps
tan(e)
".
Transcribed Image Text:Solution Just before slipping, we say that the block is still at rest, so the net force on the x-axis is: EFx=mg -f Evaluating, we get: f = mg But the frictional force is expressed as the product of coefficient and the normal force so. Ps = mg For an inclined plane. The normal force is n=mg Then, Hs=mg cos(e) so: Ps tan(e) ".
A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start
to move. Show that you can obtain the coefficient of static friction Hs by measuring the critical angle e where slipping occurs.
Problem
mg pin to
Solution
Just before slipping, we say that the block is still at rest, so the net force on the x-axis is:
ZFx=mg
Evaluating, we get:
= mg
Transcribed Image Text:A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction Hs by measuring the critical angle e where slipping occurs. Problem mg pin to Solution Just before slipping, we say that the block is still at rest, so the net force on the x-axis is: ZFx=mg Evaluating, we get: = mg
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