A block of mass m is at the top of an inclined plane of length L and angle of inclination 0. The block slides without friction down the plane and reaches the bottom. Use conservation of energy to find the block's speed at the bottom of the plane. How would you solve this problem using a force approach? Do the problem that way and see if you get the same answer.
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- An object with a mass of 12.5 kg is moving along a rough horizontal surface. At a certain point it has 66 J of kinetic energy. If the coefficient of friction between the object and the surface is 0.44, how far will the object go beyond that point before coming to a stop? Express your answer in meters, to at least one digit after the decimal point. plz help and use g = 9.8A box of 9kg is released from rest on a rough inclined plane and slides to the bottom. The plane is inclined at a 230 angle to the horizontal and it is 5.1 m high. The coefficient of kinetic friction between the box and the plane is 0.1. Use conservation of energy to determine the speed of the block as it reaches the bottom.(8c7p19) A cord is used to vertically lower an initially stationary block of mass M = 45 ką at a constant downward acceleration of q/7. When the block has fallen a distance d = 4.5 m, find the work done by the cord's force on the block. Submit Answer Tries 0/5 Find the work done by the weight of the block. Submit Answer Tries 0/5 Find the kinetic energy of the block. Submit Answer Tries 0/5 Find the speed of the block. Submit Answer Tries 0/5
- = 13 kg, and m3 20 kg, respectively, are attached by strings over frictionless pulleys as indicated in the figure below. The horizontal surface 3.4 kg, m2 %3D Three objects with masses m, exerts a force of friction of 30 N on m,. If the system is released from rest, use energy concepts to find the speed of m, after it moves down 4.0 m. m/s m2 m1 m3Several physical situations are described below. For each situation, simplify the work-energy equation by canceling any zero terms and any energy terms (whether KE or PE) which are unchanging. Explain each term which gets canceled. A cross-country skier is in motion on top of a small hill. He skis down the hill into the valley and up a second smaller hill. He uses his poles to propel himself during the entire motion. Ignore the effect of friction and air resistance. Simplification of Work-Energy Equation KEi + PEi + Wnc = KEf + PEfPlease use the information in the picture to answer the question: How fast must it have leapt from the water to reach a such a great height and speed. If you stand at the bow where you can reach up to a height of 3m above the water. You can only catch a fish if it is traveling under 8.5m/s when it reaches you. Will you be able to catch the fish? Find the speed of the fish at your location. Hint: use energy conservation.
- If the force on a particle is given as F(x,y,z) = axi + byj + czk, in which a, b and c are constants, find: a. If this force is conservative? Explain b. The potential energy associated with this force.Chapter 37, Problem 012 The length of a spaceship is measured to be exactly 1/2 its rest length. (a) What is the speed parameter ß of the spaceship relative to the observer's frame? (b) By what integer factor do the spaceship's clocks run slow, compared to clocks in the observer's frame? (a) Number Units (b) Number Units3
- A-C please!A block of mass m = 4.20 kg is released from rest from point and slides on the frictionless track shown in the figure below. (Assume h = 6.00 m.) h₂ m 3.20 m 2.00 m (a) Determine the block's speed at points and Ⓒ. point Ⓡ point Ⓒ m/s m/s (b) Determine the net work done by the gravitational force on the block as it moves from point J to point ⒸConsider a rope lowering a mass m=2.45kg at a constant speed v=8.73 m/s down a distance of d=5.72 m as shown in the figure below. c) What is the work done on the mass by the tension in the rope as it descends a distance d=5.72 m? d) What is the change in kinetic energy of the mass as it descends a distance d=5.72 m?