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A block of mass m = 8.40 kg, moving on a horizontal frictionless surface with a speed 4.20 m/s, makes a perfectly elastic collision with a block of mass M at rest. After the collision, the 8.40 block recoils with a speed of 0.400 m/s. In the figure, the blocks are in contact for 0.200 s. The magnitude of the average force on the 8.40-kg block, while the two blocks are in contact, is closest to Vi vf V M M Before After

A block of mass m = 8.40 kg, moving on a horizontal frictionless surface with a speed 4.20 m/s, makes a perfectly elastic collision with a block of mass M at rest. After the collision, the 8.40 block recoils with a speed of 0.400 m/s. In the figure, the blocks are in contact for 0.200 s. The magnitude of the average force on the 8.40-kg block, while the two blocks are in contact, is closest to Vi vf V M M Before After

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A block of mass \( m = 8.40 \, \text{kg} \), moving on a horizontal frictionless surface with a speed of \( 4.20 \, \text{m/s} \), makes a perfectly elastic collision with a block of mass \( M \) at rest. After the collision, the \( 8.40 \, \text{kg} \) block recoils with a speed of \( 0.400 \, \text{m/s} \). In the figure, the blocks are in contact for \( 0.200 \, \text{s} \). The magnitude of the average force on the \( 8.40 \, \text{kg} \) block, while the two blocks are in contact, is closest to **Diagram Explanation:** - The diagram shows two blocks on a frictionless surface. - **Before Collision:** - The block with mass \( m \) (8.40 kg) is moving to the right with an initial velocity \( v_i \). - The block with mass \( M \) is at rest. - **After Collision:** - The block with mass \( m \) moves to the left with velocity \( v_f \). - The block with mass \( M \) moves to the right with velocity \( V \). The problem involves analyzing the forces during the contact time and determining the average force experienced by the \( 8.40 \, \text{kg} \) block.
Transcribed Image Text:A block of mass \( m = 8.40 \, \text{kg} \), moving on a horizontal frictionless surface with a speed of \( 4.20 \, \text{m/s} \), makes a perfectly elastic collision with a block of mass \( M \) at rest. After the collision, the \( 8.40 \, \text{kg} \) block recoils with a speed of \( 0.400 \, \text{m/s} \). In the figure, the blocks are in contact for \( 0.200 \, \text{s} \). The magnitude of the average force on the \( 8.40 \, \text{kg} \) block, while the two blocks are in contact, is closest to **Diagram Explanation:** - The diagram shows two blocks on a frictionless surface. - **Before Collision:** - The block with mass \( m \) (8.40 kg) is moving to the right with an initial velocity \( v_i \). - The block with mass \( M \) is at rest. - **After Collision:** - The block with mass \( m \) moves to the left with velocity \( v_f \). - The block with mass \( M \) moves to the right with velocity \( V \). The problem involves analyzing the forces during the contact time and determining the average force experienced by the \( 8.40 \, \text{kg} \) block.
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