1. A soccer ball is rolled off of a perfectly horizontal 10m high cliff at 5m/s. h=10m Vo=5m/s (horizontal) a. How far will it land from the cliff? X = Vot t = √2h x = NOV ²4 b. What time will it land? 4=√2h 3=38 (Conslaut)m/s² A √2.10m 3.8 m/s2 4:14 X= 5m/s2 7.14

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Hello, can you please review my work and help me to do graphs for the problems and also I need “d” problem, I can’t deal with it. Thanks for your help!
1. A soccer ball is rolled off of a perfectly horizontal 10m high cliff at 5m/s.
h=10m
Vo= 5m/s (horizontal)
a. How far will it land from the cliff?
X Vot
t=224 x=2622/12
4= √2h
9
b. What time will it land?
/60=150m/s).
angle 600
4=
X
3=3.8 (Conslaut)m/s²
t = √2·10m² t=1.433)
3.7m/s²
2. A Disney Cruise-ship decides to test its new sea monster attack mechanism by shooting a cannonball 150m/s at
an angle of 60 degrees.
a.
R=U² pin²/60°
S
9-9.80/3²/(constant)
U=0²sin²60²0
29
How far will it land? dist (R)
R=(150) 2-sin (120°)
9.8m18
C.
X= 5m/512
b. What is the maximum height it will achieve?
U=(150)2 Sin 60²
2(3.8)
5 m/s
2017/07).
2.Usin60
3
How long until it hits the water? t
t=
A
√2.10m
3.8 m/s2
4.14
- 1588.32 m
=860.96 m
2-150m/s 3in 60
5.8 m/s²
7.14
26.57 sec
d. As the ship was attempting its second test shot with the same angle and velocity, a 4,000m tall sea
monster suddenly emerged from the water 1600m away from the ship. What time will the cannonball
strike the monster?
Transcribed Image Text:1. A soccer ball is rolled off of a perfectly horizontal 10m high cliff at 5m/s. h=10m Vo= 5m/s (horizontal) a. How far will it land from the cliff? X Vot t=224 x=2622/12 4= √2h 9 b. What time will it land? /60=150m/s). angle 600 4= X 3=3.8 (Conslaut)m/s² t = √2·10m² t=1.433) 3.7m/s² 2. A Disney Cruise-ship decides to test its new sea monster attack mechanism by shooting a cannonball 150m/s at an angle of 60 degrees. a. R=U² pin²/60° S 9-9.80/3²/(constant) U=0²sin²60²0 29 How far will it land? dist (R) R=(150) 2-sin (120°) 9.8m18 C. X= 5m/512 b. What is the maximum height it will achieve? U=(150)2 Sin 60² 2(3.8) 5 m/s 2017/07). 2.Usin60 3 How long until it hits the water? t t= A √2.10m 3.8 m/s2 4.14 - 1588.32 m =860.96 m 2-150m/s 3in 60 5.8 m/s² 7.14 26.57 sec d. As the ship was attempting its second test shot with the same angle and velocity, a 4,000m tall sea monster suddenly emerged from the water 1600m away from the ship. What time will the cannonball strike the monster?
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