A block of mass m = 7 kg is placed on top of a block of mass M = 10 kg, which in turn sits on a frictionless horizontal surface, as shown in the figure. A force F= 20 N is applied to the 10 kg block, and the 7 kg block is held in place by a string attatched to the wall. There is static friction between the blocks, which keeps the lower block from moving. The coefficient of static friction between the two blocks is μs = 0.5 T μ = 0 m M Hoy > 0 F

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Chapter1: Units, Trigonometry. And Vectors
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A block of mass m = 7 kg is placed on top of a block of mass M = 10 kg, which in turn sits on a
frictionless horizontal surface, as shown in the figure. A force F = 20 N is applied to the 10 kg block, and
the 7 kg block is held in place by a string attatched to the wall. There is static friction between the blocks,
which keeps the lower block from moving. The coefficient of static friction between the two blocks is
Hs = 0.5
H=0
m
Hoy > 0
F
Transcribed Image Text:A block of mass m = 7 kg is placed on top of a block of mass M = 10 kg, which in turn sits on a frictionless horizontal surface, as shown in the figure. A force F = 20 N is applied to the 10 kg block, and the 7 kg block is held in place by a string attatched to the wall. There is static friction between the blocks, which keeps the lower block from moving. The coefficient of static friction between the two blocks is Hs = 0.5 H=0 m Hoy > 0 F
2. If the string is cut so that the two blocks can accelerate together, what is the friction force between the
blocks?
(a) F =
= 49.05 N
(b) F=
11.76 N
(c) F =
8.24 N
(d) F 83.39 N
(e) F= 34.34 NX
X 0%
Transcribed Image Text:2. If the string is cut so that the two blocks can accelerate together, what is the friction force between the blocks? (a) F = = 49.05 N (b) F= 11.76 N (c) F = 8.24 N (d) F 83.39 N (e) F= 34.34 NX X 0%
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