A block of mass m = 2.50 kg is pushed d = 2.60 m along a frictionless horizontal table by a constant applied force of magnitude F = 11.0 N directed at an angle ? = 25.0° below the horizontal as shown in the figure below. (a) Determine the work done by the applied force.

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A: (a) the work done by force of gravity is, W=mgsinθsW=5.1 kg9.8 m/s2sin30.0o2.30 mW=57.5 J   (b) work…

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Q: A block of mass m = 2.50 kg is pushed d = 2.00 m along a frictionless horizontal table by a constant…

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A: According to question--- Given data-- Tension  = 1.54 × 104 N. Mass of elevator m = 1.40 × 103 kg.…

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Q: A block of mass 2.50 kg is pushed 2.20 m along a frictionless horizontal table by a constant 16.0-N…

A: mass = 2.50 Kg d = 2.20  F = 16N directed towards below the horizontal

Q: A block of mass 2.50 kg is pushed 3.00 m along a frictionless horizontal table by a constant 16.0 N…

A:

Q: 2.50 kg is pushed d = 2.30 m along a frictionless horizontal table by a constant applied force of…

A: mass of object                            m = 2.50 kg  Distance block pushed…

Q: A 55 kg block is pulled along the ground for a distance of 7.1 m by a 89 N force at an angle of 41…

A: work done can be calculated as, W=Fdcosθ,

Q: A cable exerts a constant upward tension of magnitude 2.54 × 10“ N on a 2.40 x 10° kg elevator as it…

A: Work done=FdcosθF is tension force=2.54×104 Nd is vertical distance=3.10 mθ is angle between force…

Q: A)Find the work done by each force acting on the rock during this motion, in units of Joules. There…

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A: The expression for the work done is W=F·d=Fdcosθ The force of friction acts in the direction…

Q: block of mass m = 2.50 kg is pushed d = 2.10 m along a frictionless horizontal table by a constant…

A: As per our guidelines, we are supposed to answer only first three subparts in case of multiple…

Q: A block of mass m = 2.50 kg is pushed d = 2.30 m along a frictionless horizontal table by figure…

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A: Mass of block(m) = 6.1 lg vertical displacement (y) = 2.6 m

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Q: what is the numeric answer

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Q: The force acting on a particle varies as in the figure below. (The x axis is marked in increments of…

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A: Given data: The value for the tension is F = 165 N The angle is given as = 25.0 degree The given…

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A: (a) The work done by the force as the particles moves from x=0 to x=12.0 m, that equals the area…