A block of mass m = 2.50 kg is pushed d = 2.60 m along a frictionless horizontal table by a constant applied force of magnitude F = 11.0 N directed at an angle ? = 25.0° below the horizontal as shown in the figure below. (a) Determine the work done by the applied force.

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A: (a) the work done by force of gravity is, W=mgsinθsW=5.1 kg9.8 m/s2sin30.0o2.30 mW=57.5 J   (b) work…

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A: The work done by the force is given by  W= F→ . r→ where, F is the force and r is the displacement…

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Q: A block of mass 2.50 kg is pushed 2.20 m along a frictionless horizontal table by a constant 16.0-N…

A: mass = 2.50 Kg d = 2.20  F = 16N directed towards below the horizontal

Q: A block of mass m = 4.8 kg is placed on a rough incline surface making an angle 0 = 24.2• with…

A:

Q: A block of mass 2.50 kg is pushed 3.00 m along a frictionless horizontal table by a constant 16.0 N…

A:

Q: 2.50 kg is pushed d = 2.30 m along a frictionless horizontal table by a constant applied force of…

A: mass of object                            m = 2.50 kg  Distance block pushed…

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A: work done can be calculated as, W=Fdcosθ,

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A: The work done is given by  W = F s cos A where, F is the force, s is the displacement and A is the…

Q: A cable exerts a constant upward tension of magnitude 2.54 × 10“ N on a 2.40 x 10° kg elevator as it…

A: Work done=FdcosθF is tension force=2.54×104 Nd is vertical distance=3.10 mθ is angle between force…

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Q: A)Find the work done by each force acting on the rock during this motion, in units of Joules. There…

A: Data provided in the question; Mass of rock (M)=30 kg  Force applied on the rock (P)=200 N Angle…

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A: As per our guidelines, we are supposed to answer only first three subparts in case of multiple…

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A: Solution:-Given thatmass of box (m)=102 kgdisplacement (d)=4 mcoefficient of friction (μ)=0.5Force…

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A: distance moved (d) = 42.6 meters constant applied force (F) = 118.1 N θ = 37.2ofrictional force (f)…

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A: This question can be easily solved by applying the basic concept of friction and energy…

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Q: A 6.1-kg block is pushed 2.6 m up a vertical wall with constant speed by a constant force of…

A: Mass of block(m) = 6.1 lg vertical displacement (y) = 2.6 m

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A: Given that, Mass of crate M = 287 kg angle below the horizontal direction Θ =17.1 0 the coefficient…

Q: what is the numeric answer

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Q: A box of mass 20.0 [kg] slides down from the op of a surface inclined at 50.0° with height of 10.0…

A: Given: The mass of box is 20.0 kg.             The angle of the box with horizontal is 50.0°.…

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Q: A 287-kg crate is being pushed across a horizontal floor by a force P that makes an angle of 17.1°…

A: The mass m=287 kg The angle θ=17.1° The coefficient of kinetic fraction μk=0.253

Q: The force acting on a particle varies as in the figure below. (The x axis is marked in increments of…

A: the work done is area under the curvea)the work done is w=0.5*b*h.where b is base of the triangle…

Q: A tension force of 165 N inclined at 25.0° above the horizontal is used to pull a 39.0 kg storage…

A: Given data: The value for the tension is F = 165 N The angle is given as = 25.0 degree The given…

Q: The force acting on a particle varies as in the figure below. (The x axis is marked in increments of…

A: (a) The work done by the force as the particles moves from x=0 to x=12.0 m, that equals the area…