A block of mass m = 2.00 kg is attached to a spring of force constant k = 4.95 x 102 N/m that lies on a horizontal frictionless surface as shown in the figure below. The block is pulled to a position x, = 4.10 cm to the right of equilibrium and released from rest. x= 0 x= x; (a) Find the the work required to stretch the spring. (b) Find the speed the block has as it passes through equilibrium. m/s

A block of mass m = 2.00 kg is attached to a spring of force constant k = 4.95 x 102 N/m that lies on a horizontal frictionless surface as shown in the figure below. The block is pulled to a position x, = 4.10 cm to the right of equilibrium and released from rest. x= 0 x= x; (a) Find the the work required to stretch the spring. (b) Find the speed the block has as it passes through equilibrium. m/s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: When a 2.30-kg object is hung vertically on a certain light spring described by Hooke's law, the…

Q: m = 5.20 kg is sliding across a horizontal frictionless surface with an initial speed vi = 3.30 m/s…

Q: When a 2.40-kg object is hung vertically on a certain light spring described by Hooke's law, the…

A: Given: The mass of the object is 2.4 kg. The spring constant is 2.58 cm.

Q: An ideal spring has a spring constant k=28.2 N/m. What is the amount of work that must be done to…

Q: When a 3.70-kg object is hung vertically on a certain light spring that obeys Hooke's law, the…

A: Given: Mass of object = 3.7 kg Spring stretches, x = 2.6 cm=2.6 X 10-2 m

Q: SQU is trying a new particle accelerator design with a mechanical component using a spring that does…

A: F= 51.6x4 + 55.6x3x1 = 0.7 m x2 = 1.1 m

Q: The force required to stretch a slingshot by different amounts is shown in the graph below. (a)…

Q: At an archery event, a woman draws the string of her bow back 0.390 m with a force that increases…

Q: A 40.0° 1.50 m B 1.00 m C k = 900 N/m mm hh

A: Mass of block (m) = 2.50 kgBlock starts from rest at point A at the top of a 1.50 m long…

Q: A block of mass m= 0.28 kg is resting against the spring with force constant K= 250 N/m and…

A: Given: The mass of the object is 0.28 kg. The spring constant is 250 N/m. The compression in the…

Q: A 2.00kg block is pushed against a spring with negligible mass and force constant k = 350 N/m ,…

Q: The 7.00 kg object shown below is released from rest at a height of 8.0 m on a curved frictionless…

A: SOlution: given that m = 7 kg h = 8 m force constant k = 600 N/m

Q: A block of mass m= 0.28 kg is resting against the spring with force constant K= 250 N/m and…

A: We have a block of mass m=0.28 kg which is connected to a spring of force constant K=250 N/m…

Q: A bungee jumper with a mass of 77.5 kg is standing on a platform 65.1 m above a lake. The length of…

A: Give: m = 77.5kg h0 = 65.1m L0 = 15.3m K = 155N/m h1 = 47.7m V1 = ?

Q: spring laying HORIZONTALLY on a flat surface is compressed 4.5 cm (convert to m), and a ball is…

A: Given:- A spring laying in the horizontal. Displacement of the compressed spring x = 4.5 cm =…

Q: A block of mass 1.4 kg is attached to the right end of horizontal spring (left end is attached to a…

Q: A spring with spring constant k = 190 N/m is suspended vertically with its upper end fixed to the…

A: NOTE: As per guidelines, I can solve the first three parts of the problem. If you need help with…

Q: A block of mass 4.00 kg is placed against a horizontal spring of constant k = 835 N/m and pushed so…

A: Elastic potential energy can be defined as the energy stored when an elastic object is stretched or…

Q: A spring with constant k = 90 N / m stores 45.0 J of energy when it is compressed a distance d. Find…

A: The given data are: k=90 N/mU=45 Jd1=1.5d

Q: 13. A 4.50-kg child is swinging on a swing. If she is released from rest at a point 1.45 m above the…

Q: In the block–spring arrangement of the figure, the block’s mass is 3.30 kg and the spring constant…

Q: When a force of 120.0 N is applied to a certain spring, it causes a stretch of 2.25 cm. What is the…

Q: You push a 2.00 kg block against a horizontal spring, compressing the spring by 15.0 cm. Then you…

A: Given Mass of block is m= 2.00 kg Compressed distance of spring is x=15.0 cm=0.15 m Spring constant…

Q: A 2.50 kg textbook is forced against one end of a horizontalspring of negligible mass that is fixed…

A: Given, Mass of the book, m=2.5 kg Force constant, k=250 N/m Kinetic friction, μk=0.3 Initially the…

Q: Find the potential energy of a spring that has been stretched by a 10.0 N force, displaced from the…

A: Potential Energy of spring is given by k=-Fx U=12k∆x2 Given : Force F = 10 N x1=0x2=10 cm =0.1 m…

Q: When a 2.60-kg object is hung vertically on a certain light spring described by Hooke's law, the…

Q: A 3 kg object attached to an ideal massless spring is compressed 1.2 m. If the spring constant is 45…

Q: A 2.0 kg object is acted upon by a spring force characterized by the function F=-6x, (this means k =…

Q: The 5.00 kg object shown below is released from rest at a height of 7.0 m on a curved frictionless…

A: Given, m=5 kg h=7 m k= 500 N/m g= 9.8 m/s²

Q: 2) The force required to stretch a slingshot by different amounts is shown in the graph below. (a)…

Concept explainers

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest. 

Question

A block of mass m =
2.00 kg is attached to a spring of force constant k = 4.95 x 102 N/m that lies on a horizontal frictionless surface as shown in the figure
below. The block is pulled to a position x;
= 4.10 cm to the right of equilibrium and released from rest.
k
m
x= 0
x= x;
(a) Find the the work required to stretch the spring.
(b) Find the speed the block has as it passes through equilibrium.
m/s

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

It takes a force of 5.00 N to stretch an ideal spring 2.00 cm. (a) What force does it take to stretch the spring an additional 4.00 cm? (b) By what factor does the stored elastic potential energy increase when the spring, originally stretched 2.00 cm, is stretched 4.00 cm more?
Pushing on the pump of a bottle of hand washing solution compresses a small spring which obeys Hooke's Law. If the potential energy of the spring is 0.0030 J when the spring is compressed 0.53 cm, determine the following. (a) the force constant (in kN/m) of the spring (b) the compression (in cm) needed in order for the spring potential energy to equal 0.0085 J
how do you slove
When a 2.00-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.68 cm. (a) What is the force constant of the spring? N/m (b) If the 2.00-kg object is removed, how far will the spring stretch if a 1.00-kg block is hung on it? cm (c) How much work must an external agent do to stretch the same spring 6.50 cm from its unstretched position? J
(a) The figure below shows an 8.00 kg stone at rest on a spring. The spring is compressed 10.0 cm by the stone. (a) What is the spring constant? (b) The stone is pushed down an additional 30.0 cm and released. What is the elastic potential energy of the compressed spring just before that release? (c) What is the change in the gravi- tational potential energy of the stone-Earth system when the stone moves from the release point to its maximum height? (d) What is that maximum height, measured from the release point? 00000
As shown in the figure, a 1.50 kg box is held at rest against a spring with a force constant k = 725 N/m that is compressed a distance d. When the box is released, it slides across a surface that is frictionless, except for a rough patch that has a coefficient of kinetic friction μk = 0.47 and is 6.0 cm in length. (a) Calculate the spring's potential energy in terms of d d2 (b) Calculate the magnitude of the friction force (in N). N (c) Calculate the work done by the frictional force (in J). Be sure to include the correct sign in your answer. J (d) The speed of the box is 1.9 m/s after sliding across the rough patch. Calculate the initial compression d (in cm) of the spring. cm
A large block with a mass of 8.5 kg slides along a horizontal surface without friction. The block runs into ahorizontal spring with a spring constant of 260 N/m and compresses the spring by 50 cm before coming to astop.(a) How fast is the block moving when it just hit the spring?(b) What is the potential energy of the spring, the kinetic energy of the block, and the total mechanicalenergy of the system when the block is halfway to its stopping position?
A mass of 0.75 kg is suspended from a spring. If 1.41 J of work is done against the spring as the mass is pulled 0.15 m away from its equilibrium position, what is the spring constant of the spring?
When a 2.30-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.99 cm. (a) What is the force constant of the spring? N/m (b) If the 2.30-kg object is removed, how far will the spring stretch if a 1.15-kg block is hung on it? cm (c) How much work must an external agent do to stretch the same spring 9.30 cm from its unstretched position? J Need Help2
An archer pulls her bowstring back 0.398 m by exerting a force that increases uniformly from zero to 231 N. (a) What is the equivalent spring constant of the bow? N/m (b) How much work does the archer do on the string in drawing the bow?
answer part b
A 2.0 kg object is acted upon by a spring force characterized by the function F=-6x, (this means k = -6N/m). The speed of the object at x=3.0 m is 8.0 m/s. Determine the positive value for x where the speed of the object will be 4.9 m/s. Hint: The work done between values of x will be 1/2kx22-1/2kx12. Set this equal to the change in kinetic energy associated with the change in speed.