A binomial experiment with probability of success p=0.4 and n=5 trials is conducted. What is the probability that the experiment results in exactly 1 success? Do not round your intermediate computations, and round your answer to three decimal places. (If necessary, consult a list of formulas.) 0 S ?

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### Binomial Probability Calculation

**Problem Statement:**

A binomial experiment with a probability of success \( p = 0.4 \) and \( n = 5 \) trials is conducted. What is the probability that the experiment results in exactly 1 success?

Do not round your intermediate computations, and round your answer to three decimal places. (If necessary, consult a list of formulas.)

---

### Explanation

In binomial experiments, the probability of exactly \( k \) successes in \( n \) trials is given by:

\[ P(X = k) = \binom{n}{k} p^k (1 - p)^{n-k} \]

Where:

- \( n \) is the number of trials
- \( k \) is the number of successes
- \( p \) is the probability of success on a single trial
- \( \binom{n}{k} \) is the binomial coefficient, calculated as:

\[ \binom{n}{k} = \frac{n!}{k!(n - k)!} \]

Plugging in the values from the given problem:

- \( n = 5 \)
- \( k = 1 \)
- \( p = 0.4 \)
- \( (1 - p) = 0.6 \)

So,

\[ P(X = 1) = \binom{5}{1} (0.4)^1 (0.6)^{5-1} \]

\[ P(X = 1) = 5 \cdot 0.4 \cdot (0.6)^4 \]

\[ P(X = 1) = 5 \cdot 0.4 \cdot 0.1296 \]

\[ P(X = 1) = 5 \cdot 0.05184 \]

\[ P(X = 1) = 0.2592 \]

After rounding to three decimal places, the probability that the experiment results in exactly 1 success is:

\[ \boxed{0.259} \]

Note: There are no graphs or diagrams included in this specific problem.
Transcribed Image Text:### Binomial Probability Calculation **Problem Statement:** A binomial experiment with a probability of success \( p = 0.4 \) and \( n = 5 \) trials is conducted. What is the probability that the experiment results in exactly 1 success? Do not round your intermediate computations, and round your answer to three decimal places. (If necessary, consult a list of formulas.) --- ### Explanation In binomial experiments, the probability of exactly \( k \) successes in \( n \) trials is given by: \[ P(X = k) = \binom{n}{k} p^k (1 - p)^{n-k} \] Where: - \( n \) is the number of trials - \( k \) is the number of successes - \( p \) is the probability of success on a single trial - \( \binom{n}{k} \) is the binomial coefficient, calculated as: \[ \binom{n}{k} = \frac{n!}{k!(n - k)!} \] Plugging in the values from the given problem: - \( n = 5 \) - \( k = 1 \) - \( p = 0.4 \) - \( (1 - p) = 0.6 \) So, \[ P(X = 1) = \binom{5}{1} (0.4)^1 (0.6)^{5-1} \] \[ P(X = 1) = 5 \cdot 0.4 \cdot (0.6)^4 \] \[ P(X = 1) = 5 \cdot 0.4 \cdot 0.1296 \] \[ P(X = 1) = 5 \cdot 0.05184 \] \[ P(X = 1) = 0.2592 \] After rounding to three decimal places, the probability that the experiment results in exactly 1 success is: \[ \boxed{0.259} \] Note: There are no graphs or diagrams included in this specific problem.
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