A) bimolecular elimination B) nucleophilic elimination CF3 C) bimolecular nucleophilic substitution :0: D) electrophilic addition S. -CF3 E) electrophilic elimination :0:
A) bimolecular elimination B) nucleophilic elimination CF3 C) bimolecular nucleophilic substitution :0: D) electrophilic addition S. -CF3 E) electrophilic elimination :0:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![**Classify the Type of Elementary Step**
In the diagram, an organic reaction mechanism is depicted:
- The structure on the left shows a sulfur atom (S) bonded to an oxygen (O) with a lone pair, a trifluoromethyl group (CF₃), and a chlorine atom (Cl) with a lone pair.
- The lone pairs and arrows indicate the movement of electrons. One electron pair from the oxygen moves to form a double bond with the sulfur, while the Cl leaves as a chloride ion (Cl⁻).
- The reaction results in a product where the sulfur is double-bonded to two oxygens and retains the trifluoromethyl group, while the chloride ion is depicted separately with a negative charge.
**Possible Classified Steps:**
A) Bimolecular elimination
B) Nucleophilic elimination
C) Bimolecular nucleophilic substitution
D) Electrophilic addition
E) Electrophilic elimination
This image illustrates an elimination process involving the departure of a chloride ion.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1d04afd-cb9c-4a61-ae85-e71fcb5087e6%2F1a838259-bfe0-45a8-acb6-7595dd2936bb%2F35usybk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Classify the Type of Elementary Step**
In the diagram, an organic reaction mechanism is depicted:
- The structure on the left shows a sulfur atom (S) bonded to an oxygen (O) with a lone pair, a trifluoromethyl group (CF₃), and a chlorine atom (Cl) with a lone pair.
- The lone pairs and arrows indicate the movement of electrons. One electron pair from the oxygen moves to form a double bond with the sulfur, while the Cl leaves as a chloride ion (Cl⁻).
- The reaction results in a product where the sulfur is double-bonded to two oxygens and retains the trifluoromethyl group, while the chloride ion is depicted separately with a negative charge.
**Possible Classified Steps:**
A) Bimolecular elimination
B) Nucleophilic elimination
C) Bimolecular nucleophilic substitution
D) Electrophilic addition
E) Electrophilic elimination
This image illustrates an elimination process involving the departure of a chloride ion.
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