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(a) beta emission from aluminum-30 Al He + Na Al → e + Si 13 Al + e Mg 13 Al - e + Si 30 (b) alpha emission from einsteinium-252 je + 100 Fm Es Es 252 99 He + ie + % Cf Es +e→ 252 248 Bk 252 Es 252 252 99 98 Cf (c) electron capture by molybdenum-93 He + 20 Zr je +% Nb Mo + e ie + 3 Te Mo - 92 Mo - 93 Nb 41 Mo

(a) beta emission from aluminum-30 Al He + Na Al → e + Si 13 Al + e Mg 13 Al - e + Si 30 (b) alpha emission from einsteinium-252 je + 100 Fm Es Es 252 99 He + ie + % Cf Es +e→ 252 248 Bk 252 Es 252 252 99 98 Cf (c) electron capture by molybdenum-93 He + 20 Zr je +% Nb Mo + e ie + 3 Te Mo - 92 Mo - 93 Nb 41 Mo

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter21: Nuclear Chemistry
Section: Chapter Questions
Problem 43E: A B58 atom (mass = 8.0246 amu) decays into B48 atom (mass = 8.0053 amu) by loss of a + panrticle...
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(a) beta emission from aluminum-30 13 Al → He + Na 18 Al - je + Si 18 Al + je - 2 Mg * Al e + Si 30 30 30 (b) alpha emission from einsteinium-252 252 Es je + 100 Fm 252 4 Es 248 He + Bk 97 Es e + Cf Es + e → 252 252 99 252 98 Cf (c) electron capture by molybdenum-93 Mo - He + 20 Zr je + % Nb Mo + e → ie +3 Te 92 Mo - 93 Nb 41 Mo (d) positron emission by phosphorus-28 O 28 P - He + Al + je Si ie + Si je+ 16 s 28 14 28 28 28 P.
Transcribed Image Text:(a) beta emission from aluminum-30 13 Al → He + Na 18 Al - je + Si 18 Al + je - 2 Mg * Al e + Si 30 30 30 (b) alpha emission from einsteinium-252 252 Es je + 100 Fm 252 4 Es 248 He + Bk 97 Es e + Cf Es + e → 252 252 99 252 98 Cf (c) electron capture by molybdenum-93 Mo - He + 20 Zr je + % Nb Mo + e → ie +3 Te 92 Mo - 93 Nb 41 Mo (d) positron emission by phosphorus-28 O 28 P - He + Al + je Si ie + Si je+ 16 s 28 14 28 28 28 P.
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