It is known that 1K decays to Ca (89.3%) and to 1Ar (10.5% to its first excited state, 0.2% directly to ground state). Given the atomic mass of K, Ca and 40 40 1Ar are 39.96400 [u], 39.96259 [u] and 39.96238 [u], respectively and the mass 184 energy of individual electron as well as positron is equivalent to 0.511 MeV, determine the maximum energy of both the individual electron and positron that is emitted from 1K. 40
It is known that 1K decays to Ca (89.3%) and to 1Ar (10.5% to its first excited state, 0.2% directly to ground state). Given the atomic mass of K, Ca and 40 40 1Ar are 39.96400 [u], 39.96259 [u] and 39.96238 [u], respectively and the mass 184 energy of individual electron as well as positron is equivalent to 0.511 MeV, determine the maximum energy of both the individual electron and positron that is emitted from 1K. 40
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![It is known that 1K decays to Ca (89.3%) and to 1Ar (10.5% to its first excited
state, 0.2% directly to ground state). Given the atomic mass of K, Ca and
40
1Ar are 39.96400 [u], 39.96259 [u] and 39.96238 [u], respectively and the mass
energy of individual electron as well as positron is equivalent to 0.511 MeV,
determine the maximum energy of both the individual electron and positron that is
emitted from K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F720a8abc-3aca-4255-9305-1933a12ae53c%2Fa1af852d-45ed-495a-b25b-37db396dca67%2Frr6sny_processed.jpeg&w=3840&q=75)
Transcribed Image Text:It is known that 1K decays to Ca (89.3%) and to 1Ar (10.5% to its first excited
state, 0.2% directly to ground state). Given the atomic mass of K, Ca and
40
1Ar are 39.96400 [u], 39.96259 [u] and 39.96238 [u], respectively and the mass
energy of individual electron as well as positron is equivalent to 0.511 MeV,
determine the maximum energy of both the individual electron and positron that is
emitted from K.
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