A beam of rectangular cross section has b = 22 in. and h = 15 in. It is to carry a total factored load of 3600 lb/ft uniformly distributed over its 26 ft span, and in addition the beam will be subjected to a uniformly distributed torsion of 1800 ft-lb/ft at factored loads. Closed stirrup-ties will be used to provide for flexural shear and torsion, placed with the stirrup steel centroid 1.75 in. from each concrete face. The corresponding flexural effective depth will be approximately 12.5 in. Design the transverse reinforcement for this beam and calculate the increment of longitudinal steel area needed to provide for torsion, using f=4000 psi and f₁ = 60,000 psi. S Wul will be given as Av = 0.0313 V₂ = For transverse reinforcement, use No. 4 bars. A must be estimated from shear analysis, but to save time it and T₁ = tu. To make the calculation simple, just consider the spacing required to carry the maximum V and Tu at d from the support (increasing spacing through the beam length can be skipped). The longitudinal reinforcement also needs to be calculated. in² in
A beam of rectangular cross section has b = 22 in. and h = 15 in. It is to carry a total factored load of 3600 lb/ft uniformly distributed over its 26 ft span, and in addition the beam will be subjected to a uniformly distributed torsion of 1800 ft-lb/ft at factored loads. Closed stirrup-ties will be used to provide for flexural shear and torsion, placed with the stirrup steel centroid 1.75 in. from each concrete face. The corresponding flexural effective depth will be approximately 12.5 in. Design the transverse reinforcement for this beam and calculate the increment of longitudinal steel area needed to provide for torsion, using f=4000 psi and f₁ = 60,000 psi. S Wul will be given as Av = 0.0313 V₂ = For transverse reinforcement, use No. 4 bars. A must be estimated from shear analysis, but to save time it and T₁ = tu. To make the calculation simple, just consider the spacing required to carry the maximum V and Tu at d from the support (increasing spacing through the beam length can be skipped). The longitudinal reinforcement also needs to be calculated. in² in
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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