A beam of electrons, each with the same ki- netic energy, illuminates a pair of slits sepa rated by a distance of 63 nm. The beam forms bright and dark fringes on a screen located a distance 1.1 m beyond the two slits. The arrangement is otherwise identical to that used in the optical two-slit interference experiment. The bright fringes are found to be separated by a distance of 0.1 mm. What is the kinetic energy of the elec- trons in the beam? Planck’s constant is 6.63 × 10^−34 J · s. Answer in units of keV.
A beam of electrons, each with the same ki- netic energy, illuminates a pair of slits sepa rated by a distance of 63 nm. The beam forms bright and dark fringes on a screen located a distance 1.1 m beyond the two slits. The arrangement is otherwise identical to that used in the optical two-slit interference experiment. The bright fringes are found to be separated by a distance of 0.1 mm. What is the kinetic energy of the elec- trons in the beam? Planck’s constant is 6.63 × 10^−34 J · s. Answer in units of keV.
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Chapter1: Units, Trigonometry. And Vectors
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A beam of electrons, each with the same ki- netic energy, illuminates a pair of slits sepa rated by a distance of 63 nm. The beam forms bright and dark fringes on a screen located a distance 1.1 m beyond the two slits. The arrangement is otherwise identical to that used in the optical two-slit interference experiment. The bright fringes are found to be separated by a distance of 0.1 mm.
What is the kinetic energy of the elec- trons in the beam? Planck’s constant is 6.63 × 10^−34 J · s.
Answer in units of keV.
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