In the double-slit interference pattern for helium atoms, the kinetic energy of the beam of atoms was 0.020 eV. What is the de Broglie wavelength of a helium atom with this kinetic energy?
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- An electron is moving at 1.00 km per second. What is it's de Broglie wavelength? Show the algebraic form of all equation(s) applied and report your final answer with the correct units and number of significant figures.Electrons with an energy of 0.842 eV are incident on a double slit in which the two slits are separated by 40.0 nm. What is the de Broglie wavelength (in nanometers!) of these electrons?A) After a 0.790 nm x-ray photon scatters from a free electron, the electron recoils with a speed equal to 1.59E+6 m/s. What was the Compton shift in the photon's wavelength? B) Through what angle was the photon scattered?
- An electron is accelerated from rest through a potential difference so that its de Broglie wavelength is 0.020 nm. What is the potential difference?Assuming that the smallest measurable wavelength in an experiment is 0.650 fm , what is the maximum mass of an object traveling at 815 m⋅s−1 for which the de Broglie wavelength is observable?A nickel crystal’s work function is measured to be 5.22 eV at 25°C. As the temperature increases by 300°C, the work function drops by 50 meV. By how much does this shift the threshold wavelength for photoelectric emission?