A beam is subjected to some couple moments as shown in igure and parameter table. With counter-clockwise as positive, what is the resultant couple moment? parameter L₁ L2 L3 F₁ F₂ a L₂ value 4 2 0.75 250 125 7 F₁ units ft ft ft lb lb Ꮎ F₂ F₂ cc 080 BY NO SA 2021 Cathy Zupke
A beam is subjected to some couple moments as shown in igure and parameter table. With counter-clockwise as positive, what is the resultant couple moment? parameter L₁ L2 L3 F₁ F₂ a L₂ value 4 2 0.75 250 125 7 F₁ units ft ft ft lb lb Ꮎ F₂ F₂ cc 080 BY NO SA 2021 Cathy Zupke
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![**Problem Statement:**
A beam is subjected to some couple moments as shown in the figure and parameter table. With counter-clockwise as positive, what is the resultant couple moment?
**Diagram Explanation:**
The diagram shows a beam with two forces, \( F_1 \) and \( F_2 \), applied at different points and angles. The force \( F_1 \) acts horizontally to the left and vertically downward with an applied distance \( L_1 \) from the left end of the beam. Force \( F_2 \) is inclined at an angle \( \theta \) with respect to the horizontal, applied twice due to symmetry, and acts at a horizontal distance \( L_3 \).
**Parameter Table:**
\[
\begin{array}{|c|c|c|}
\hline
\text{parameter} & \text{value} & \text{units} \\
\hline
L_1 & 4 & \text{ft} \\
L_2 & 2 & \text{ft} \\
L_3 & 0.75 & \text{ft} \\
F_1 & 250 & \text{lb} \\
F_2 & 125 & \text{lb} \\
\theta & 75 & \text{°} \\
\hline
\end{array}
\]
**Resultant Moment Calculation:**
The resultant moment is calculated based on the forces and distances provided, considering counter-clockwise as positive.
The resultant moment is \(\_\_\_\_\_\) lb·ft.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e7ba281-dd87-4688-be97-9abf26130e05%2F21fe81de-b261-4c05-8611-ece09e43c8ca%2Fb03h52_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A beam is subjected to some couple moments as shown in the figure and parameter table. With counter-clockwise as positive, what is the resultant couple moment?
**Diagram Explanation:**
The diagram shows a beam with two forces, \( F_1 \) and \( F_2 \), applied at different points and angles. The force \( F_1 \) acts horizontally to the left and vertically downward with an applied distance \( L_1 \) from the left end of the beam. Force \( F_2 \) is inclined at an angle \( \theta \) with respect to the horizontal, applied twice due to symmetry, and acts at a horizontal distance \( L_3 \).
**Parameter Table:**
\[
\begin{array}{|c|c|c|}
\hline
\text{parameter} & \text{value} & \text{units} \\
\hline
L_1 & 4 & \text{ft} \\
L_2 & 2 & \text{ft} \\
L_3 & 0.75 & \text{ft} \\
F_1 & 250 & \text{lb} \\
F_2 & 125 & \text{lb} \\
\theta & 75 & \text{°} \\
\hline
\end{array}
\]
**Resultant Moment Calculation:**
The resultant moment is calculated based on the forces and distances provided, considering counter-clockwise as positive.
The resultant moment is \(\_\_\_\_\_\) lb·ft.
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