A beam contains 7.8 x 106 doubly charged positive ions per cubic centimeter, all of which are moving north with a speed of 7.3 x 105 m/s. What is (a) the magnitude of the current density and (b) direction of the current density J .(c) What additional quantity do you need to calculate the total current i in this ion beam? (a) Number i Units (b)

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### Problem Statement: Ion Beam Current Density Calculation

A beam contains \( 7.8 \times 10^6 \) doubly charged positive ions per cubic centimeter, all of which are moving north with a speed of \( 7.3 \times 10^5 \) m/s. 

#### Questions:
1. **(a)** What is the magnitude of the current density \( \mathbf{J} \)?
2. **(b)** What is the direction of the current density \( \mathbf{J} \)?
3. **(c)** What additional quantity do you need to calculate the total current \( I \) in this ion beam?

#### Inputs:
- **Ion Density**: \( 7.8 \times 10^6 \) ions/cm\(^3\)
- **Charge per Ion**: Doubly charged positive ions (each ion carries a charge of \( 2e \))
- **Ion Velocity**: \( 7.3 \times 10^5 \) m/s north

#### Outputs:
1. **(a)** 
   - **Number:**
    \[ \boxed{} \]
   - **Units:** 
    \[ \boxed{\text{}} \]

2. **(b)**
   \[ \boxed{} \]

3. **(c)**
   \[ \boxed{} \]

This problem requires calculating the current density in a beam of ions, determining its direction, and identifying additional quantities needed to compute the total current in the beam. The magnitude of current density \(\mathbf{J}\) can be derived from the product of the charge density and velocity.
Transcribed Image Text:### Problem Statement: Ion Beam Current Density Calculation A beam contains \( 7.8 \times 10^6 \) doubly charged positive ions per cubic centimeter, all of which are moving north with a speed of \( 7.3 \times 10^5 \) m/s. #### Questions: 1. **(a)** What is the magnitude of the current density \( \mathbf{J} \)? 2. **(b)** What is the direction of the current density \( \mathbf{J} \)? 3. **(c)** What additional quantity do you need to calculate the total current \( I \) in this ion beam? #### Inputs: - **Ion Density**: \( 7.8 \times 10^6 \) ions/cm\(^3\) - **Charge per Ion**: Doubly charged positive ions (each ion carries a charge of \( 2e \)) - **Ion Velocity**: \( 7.3 \times 10^5 \) m/s north #### Outputs: 1. **(a)** - **Number:** \[ \boxed{} \] - **Units:** \[ \boxed{\text{}} \] 2. **(b)** \[ \boxed{} \] 3. **(c)** \[ \boxed{} \] This problem requires calculating the current density in a beam of ions, determining its direction, and identifying additional quantities needed to compute the total current in the beam. The magnitude of current density \(\mathbf{J}\) can be derived from the product of the charge density and velocity.
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