A beam contains 2.7 x 109 doubly charged positive ions per cubic centimeter, all of which are moving north with a speed of 4.9 x 105 m/s. What is (a) the magnitude of the current density and (b) direction of the current density . (c) What additional quantity do you need to calculate the total current i in this ion beam? (a) Number Units A/m^2 to the north (b) cross-sectional area of ion beam (c) Use correct number of significant digits; the tolerance is +/-1 in the 2nd significant digit

icon
Related questions
Question
### Problem Statement:

A beam contains \(2.7 \times 10^9\) doubly charged positive ions per cubic centimeter, all of which are moving north with a speed of \(4.9 \times 10^5\) m/s. 

### Questions:
1. **(a)** What is the magnitude of the current density \( \vec{J} \)?
2. **(b)** What is the direction of the current density \( \vec{J} \)?
3. **(c)** What additional quantity do you need to calculate the total current \( i \) in this ion beam?

### Answers:

- **(a)** Number: [Input field], Units: [A/m\(^2\)]
- **(b)** Direction: [to the north] (Check box selected)
- **(c)** Additional quantity: [cross-sectional area of ion beam] (Check box selected)

### Note:

Use the correct number of significant digits; the tolerance is +/-1 in the second significant digit.
Transcribed Image Text:### Problem Statement: A beam contains \(2.7 \times 10^9\) doubly charged positive ions per cubic centimeter, all of which are moving north with a speed of \(4.9 \times 10^5\) m/s. ### Questions: 1. **(a)** What is the magnitude of the current density \( \vec{J} \)? 2. **(b)** What is the direction of the current density \( \vec{J} \)? 3. **(c)** What additional quantity do you need to calculate the total current \( i \) in this ion beam? ### Answers: - **(a)** Number: [Input field], Units: [A/m\(^2\)] - **(b)** Direction: [to the north] (Check box selected) - **(c)** Additional quantity: [cross-sectional area of ion beam] (Check box selected) ### Note: Use the correct number of significant digits; the tolerance is +/-1 in the second significant digit.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions