An aluminum wire 1.024 mm in diameter (18-gauge) carries a current of 4 amps. Overall Hint a. What is the number density of charge carriers (electrons) in the wire? Hint for (a) 1 The number density of electrons in the wire is m³ (Use "E" notation to enter your answer in scientific notation. For example, to enter 3.14 x 10¹2, enter "3.14E12".) b. What is the magnitude of the drift velocity of the electrons? Hint for (b) The drift velocity of the electrons is vd = c. What would be the drift velocity if the same gauge copper were used instead of aluminum? Hint for (c) For the same gauge copper wire, the drift velocity would be vd = m/s. m/s. There is a disconnect between how small drift velocities are and how quickly electrical signals travel through wires (nearly at the speed of light). For the moment, treat the two as completely unrelated to each other.

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An aluminum wire 1.024 mm in diameter (18-gauge) carries a current of 4 amps.
Overall Hint
a. What is the number density of charge carriers (electrons) in the wire?
Hint for (a)
1
The number density of electrons in the wire is
m³
(Use "E" notation to enter your answer in scientific notation. For example, to enter 3.14 x 10¹2, enter
"3.14E12".)
b. What is the magnitude of the drift velocity of the electrons?
Hint for (b)
The drift velocity of the electrons is vd =
c. What would be the drift velocity if the same gauge copper were used instead of aluminum?
Hint for (c)
For the same gauge copper wire, the drift velocity would be vd =
m/s.
m/s.
There is a disconnect between how small drift velocities are and how quickly electrical signals travel through
wires (nearly at the speed of light). For the moment, treat the two as completely unrelated to each other.
Transcribed Image Text:An aluminum wire 1.024 mm in diameter (18-gauge) carries a current of 4 amps. Overall Hint a. What is the number density of charge carriers (electrons) in the wire? Hint for (a) 1 The number density of electrons in the wire is m³ (Use "E" notation to enter your answer in scientific notation. For example, to enter 3.14 x 10¹2, enter "3.14E12".) b. What is the magnitude of the drift velocity of the electrons? Hint for (b) The drift velocity of the electrons is vd = c. What would be the drift velocity if the same gauge copper were used instead of aluminum? Hint for (c) For the same gauge copper wire, the drift velocity would be vd = m/s. m/s. There is a disconnect between how small drift velocities are and how quickly electrical signals travel through wires (nearly at the speed of light). For the moment, treat the two as completely unrelated to each other.
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