A beam ABC is pin-jointed at points A and B and is shown below. Calculate the maximum bending moment in kNm using anticlockwise moment as negative. Y X 3kN A 40kN 75 kN/m B C 0.5 m 0.25 m 0.25 m 0.75 m A 2M B 0.45 Steel brass 701 Torque supponed by steel TS = 0.7TT Total :. Tb = 0·35+ Torque OAC = 0 BC + OAB OAC = 0 · OBC = OAB Ts Ls GsJs " 077-(0.45) Tb Lb GbJb 75×10 6 x πTds² 0.4315 32 2 75X106X Tids² 32 0315 x 32 GS 75MPa Gb = 40MP : db = • 90mm ds = ? 0.37 + ( 2 ) T 40x106x 7d2b = 0-6 11 75x106x πds 2 10.08 32 40×106x πdb² 32 11 75 X 10.6 x πids 2 0-6x32 40 x 106 x 71 x0.092 19.2 400106 XA CO09) 10.08 x 40×106 XπT(0.09)² = 19.2 (75×106) x 77052 ds = 47.62mm X 65.47mm
A beam ABC is pin-jointed at points A and B and is shown below. Calculate the maximum bending moment in kNm using anticlockwise moment as negative. Y X 3kN A 40kN 75 kN/m B C 0.5 m 0.25 m 0.25 m 0.75 m A 2M B 0.45 Steel brass 701 Torque supponed by steel TS = 0.7TT Total :. Tb = 0·35+ Torque OAC = 0 BC + OAB OAC = 0 · OBC = OAB Ts Ls GsJs " 077-(0.45) Tb Lb GbJb 75×10 6 x πTds² 0.4315 32 2 75X106X Tids² 32 0315 x 32 GS 75MPa Gb = 40MP : db = • 90mm ds = ? 0.37 + ( 2 ) T 40x106x 7d2b = 0-6 11 75x106x πds 2 10.08 32 40×106x πdb² 32 11 75 X 10.6 x πids 2 0-6x32 40 x 106 x 71 x0.092 19.2 400106 XA CO09) 10.08 x 40×106 XπT(0.09)² = 19.2 (75×106) x 77052 ds = 47.62mm X 65.47mm
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
Please see below
I have attempted but I don't know where I have gone wrong, please correct my mistakes using the SAME method (section method for a pinned beam)
correct answer = -24.07kNm
Transcribed Image Text:A beam ABC is pin-jointed at points A and B and is shown below. Calculate the maximum bending moment in kNm using
anticlockwise moment as negative.
Y
X
3kN
A
40kN
75 kN/m
B
C
0.5 m
0.25 m
0.25 m
0.75 m
Transcribed Image Text:A
2M
B
0.45
Steel
brass
701 Torque supponed by steel
TS = 0.7TT Total
:. Tb = 0·35+
Torque
OAC = 0 BC + OAB
OAC = 0
· OBC = OAB
Ts Ls
GsJs
"
077-(0.45)
Tb Lb
GbJb
75×10 6 x πTds²
0.4315
32
2
75X106X Tids²
32
0315 x 32
GS
75MPa
Gb = 40MP
:
db =
• 90mm
ds = ?
0.37 + ( 2 )
T
40x106x 7d2b
=
0-6
11
75x106x πds 2
10.08
32
40×106x πdb²
32
11
75 X 10.6 x πids 2
0-6x32
40 x 106 x 71 x0.092
19.2
400106 XA CO09)
10.08 x 40×106 XπT(0.09)² = 19.2 (75×106) x 77052
ds = 47.62mm
X
65.47mm
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