A battery with potential emf is connected with two resistors (resistances R and 2R), a capacitor (capacitance C), and a switch to close and open the circuit as shown. Assume all of the connecting wires have zero resistance. emf + R w 2R switch 1. [8pts] Write down the the node rule relating the currents IR and I2R flowing through the two resistors and the current Ic flowing to the capacitor, and all the loop rules that apply to this circuit when the switch is closed. Use the variable Q for the magnitude of the charge on the capacitor plates. 2. [9pts] Suppose that initially the capacitor is uncharged, and the switch is open. Then the switch is closed. Using the equations you found above, determine the currents IR, I2R, and Ic immediately after closing the switch.

Q: Part A A 10.0F capacitor initially charged to 30.0 C is discharged through a 2.40 k2 resistor. How…

A: Capacitance of capacitor is   C= 10×10-6 FResistance of resistor  Initial charge q0 =30Cq0=30×10-6…

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Q: R, R, R. R.

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Q: R = 4 2 B R2 = 32 = 12 V I=8V E R3 = 22 с.

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