### Electrical Resistance in a Hair Dryer: Educational ExerciseA **120-V hair dryer** has two power settings: **950 W** and **1500 W**.#### Part BDetermine the resistance at the **950 W** setting.- **Instructions:** Express your answer to two significant figures and include the appropriate units. - **Given Solution:** \[ R_1 = 15 \, \Omega \] - **Status:** Correct#### Part CDetermine the resistance at the **1500 W** setting.- **Instructions:** Express your answer to two significant figures and include the appropriate units. - Use the formula for electrical resistance: \[ R = \frac{V^2}{P} \] - Where $ R $ is resistance, $ V $ is voltage, and $ P $ is power.- **Input Box:** Enter the calculated resistance $ R_2 $ in ohms (Ω).**Resources:**- **Pearson Education, Inc.** (2022). All rights reserved.- **Links:** Terms of Use | Privacy Policy | Permissions | Contact UsThis exercise helps users understand how to apply electrical formulas to calculate resistance for different power settings, enhancing problem-solving skills in real-world applications. **Problem Statement:**A 120-V hair dryer has two settings: 950 W and 1500 W.**Part C:**Determine the resistance at 1500 W setting.Express your answer to two significant figures and include the appropriate units.**Answer Input:**- A field to enter the resistance value in ohms (Ω).**Status:**- The answer is marked incorrect.- Instruction: Try again; 5 attempts remaining.**Additional Context:**- The input box is labeled `R_2`.- A submit button and options for previous answers and request answer are provided.**Note:**The task requires applying the formula $ P = \frac{V^2}{R} $ to find resistance $ R $, where $ P $ is power, $ V $ is voltage, and $ R $ is resistance.

Given, An operating Voltage of hair dryers, V = 120 V Power, P1 = 950 WP2 = 1500 W

Answered: A 120-V hair dryer has two settings:…

Science

Physics

A 120-V hair dryer has two settings: 950 W and 1500 W

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

### Electrical Resistance in a Hair Dryer: Educational Exercise

A **120-V hair dryer** has two power settings: **950 W** and **1500 W**.

#### Part B
Determine the resistance at the **950 W** setting.

- **Instructions:** Express your answer to two significant figures and include the appropriate units.

- **Given Solution:**
\[
R_1 = 15 \, \Omega
\]
- **Status:** Correct

#### Part C
Determine the resistance at the **1500 W** setting.

- **Instructions:** Express your answer to two significant figures and include the appropriate units.

- Use the formula for electrical resistance:
\[
R = \frac{V^2}{P}
\]
- Where $ R $ is resistance, $ V $ is voltage, and $ P $ is power.

- **Input Box:** Enter the calculated resistance $ R_2 $ in ohms (Ω).

**Resources:**

- **Pearson Education, Inc.** (2022). All rights reserved.
- **Links:** Terms of Use | Privacy Policy | Permissions | Contact Us

This exercise helps users understand how to apply electrical formulas to calculate resistance for different power settings, enhancing problem-solving skills in real-world applications.

**Problem Statement:**

A 120-V hair dryer has two settings: 950 W and 1500 W.

**Part C:**

Determine the resistance at 1500 W setting.

Express your answer to two significant figures and include the appropriate units.

**Answer Input:**

- A field to enter the resistance value in ohms (Ω).

**Status:**

- The answer is marked incorrect.
- Instruction: Try again; 5 attempts remaining.

**Additional Context:**

- The input box is labeled `R_2`.
- A submit button and options for previous answers and request answer are provided.

**Note:**

The task requires applying the formula $ P = \frac{V^2}{R} $ to find resistance $ R $, where $ P $ is power, $ V $ is voltage, and $ R $ is resistance.

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99. Subject Physics
Photo by Kwines A B D 154 mA 75 A 139 mA 2A www R₁=200 E- R₂=500 R₂=200 10V ww www R₁=500 ⠀ 1