A batch of wet solid was dried on a tray dryer using constant drying conditions and a thickness of material on the tray of 25.4 mm. Only the top surface was exposed. The drying rate during the constant-rate period was R = 2.05 kg H2O/h. m2. The ratio Ls/A used was 24.4 kg dry solid/m2 exposed surface. The initial free moisture was X1 = 0.55 and the critical moisture content Xc = 0.22 kg free moisture/kg dry solid. Calculate the time to dry a batch of this material from X1 = 0.45 to X2 = 0.30 using the same drying conditions but a thickness of 50.8 mm, with drying from the top and bottom surfaces.
A batch of wet solid was dried on a tray dryer using constant drying conditions and a thickness of material on the tray of 25.4 mm. Only the top surface was exposed. The drying rate during the constant-rate period was R = 2.05 kg H2O/h. m2. The ratio Ls/A used was 24.4 kg dry solid/m2 exposed surface. The initial free moisture was X1 = 0.55 and the critical moisture content Xc = 0.22 kg free moisture/kg dry solid. Calculate the time to dry a batch of this material from X1 = 0.45 to X2 = 0.30 using the same drying conditions but a thickness of 50.8 mm, with drying from the top and bottom surfaces.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A batch of wet solid was dried on a tray dryer using constant drying
conditions and a thickness of material on the tray of 25.4 mm. Only the
top surface was exposed. The drying rate during the constant-rate period
was R = 2.05 kg H2O/h. m2. The ratio Ls/A used was 24.4 kg dry
solid/m2 exposed surface. The initial free moisture was X1 = 0.55 and
the critical moisture content Xc = 0.22 kg free moisture/kg dry solid.
Calculate the time to dry a batch of this material from X1 = 0.45 to
X2 = 0.30 using the same drying conditions but a thickness of 50.8 mm,
with drying from the top and bottom surfaces.
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