A basketball has an initial launch speed of 12.0 m/s at an angle of 55° above the horizon. The basketball goes into the hoop after it has traveled a vertical displacement of 3.0 meters. Find info for X (horizontal) direction: a) Vxo = b) a = c) at the maximum height, Vx =

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A: ho=88 mvo=26 m/sθ=30°

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Q: A ball is thrown horizontally from a height of 5.50m with an initial speed of 25.0m/s.A) How long…

A: initial height (h) = 5.50 m initial velocity (u) in horizontal direction = 25 ms

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Q: A ball is thrown horizontally from a height of 5.50 m with an initial speed of 25.0 m/s. A) How long…

A: Given Initial velocity v0 = 25.0 m/s Height y0            = 5.50 m

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A: height = H = 0.33 minitial speed = V0 = 1.53 m/sangle = 560

Projectile Motion